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If $$ {x^{\sqrt{x}}}={({x{\sqrt{x}}})^{x}}$$, then the find the value of x
5Q:
If $$ {x^{\sqrt{x}}}={({x{\sqrt{x}}})^{x}}$$, then the find the value of x
- 1$$ {3\over4}$$false
- 2$$ {3\over5}$$false
- 3$$ {9\over4}$$true
- 4$$ {7\over4}$$false
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