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In ∆ABC and ∆DEF, if AB = EF, BC = DE and CA = FD, then
5Q:
In ∆ABC and ∆DEF, if AB = EF, BC = DE and CA = FD, then
- 1∆ABC ≅ ∆DEFfalse
- 2∆ABC ≅ ∆FEDfalse
- 3∆ABC ≅ ∆EFDfalse
- 4∆ABC ≅ ∆DFEtrue
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