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Q:

In an isosceles triangle, the measure of each of equal sides is 10 cm and the angle between them is 45°. the area of the triangle is

  • 1
    $$25 \ cm^2 $$
  • 2
    $$ {25\over 2}\sqrt { 2}cm^2 $$
  • 3
    $$25 \sqrt { 2} \ cm^2$$
  • 4
    $$25 \sqrt { 3} cm^2$$
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Answer : 2. "$$ {25\over 2}\sqrt { 2}cm^2 $$"

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