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In the figure given below, AD bisects ∠BAC. If the area of ΔABD=40 cm2 and AC=3AB, then the area of ΔABC:
Q:
In the figure given below, AD bisects ∠BAC. If the area of ΔABD=40 cm2 and AC=3AB, then the area of ΔABC:
- 1$$ {150 \ cm^{2}}$$false
- 2$$ {100 \ cm^{2}}$$false
- 3$$ {120 \ cm^{2}}$$true
- 4$$ {160 \ cm^{2}}$$false
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