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PQRS is square whose side is 20 cm. By joining opposite vertices of PQRS are get four triangles. What is the sum of the perimeters of the four triangles?
5Q:
PQRS is square whose side is 20 cm. By joining opposite vertices of PQRS are get four triangles. What is the sum of the perimeters of the four triangles?
- 1$$ {40{\sqrt{2}}}$$false
- 2$$ {40{\sqrt{2}}}+ 40 $$false
- 3$$ {40{\sqrt{2}}}+ 80 $$false
- 4$$ {80{\sqrt{2}}}+ 80 $$true
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