Join ExamsbookAnswer : 2. "2k1k2/k1+k2"
Two metallic plate of equal thickness and coefficient thermal conductivity K1 and K2 put together face to face. A common plate is constructed. What is equivalent K?5
Q: Two metallic plate of equal thickness and coefficient thermal conductivity K1 and K2 put together face to face. A common plate is constructed. What is equivalent K?
- 1K1k2/k1+k2false
- 22k1k2/k1+k2true
- 3K1+k2/k1k2false
- 4Nonefalse
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Answer : 2. "2k1k2/k1+k2"
Explanation :
Answer: B) 2k1k2/k1+k2 Explanation: We know that, The equivalent K = L1 + L2L1K1+L2K2 where L1 & L2 are plate1 & Plate2 thicknesses, K1 & K2 are coefficient thermal conductivity of plate1 & Plate2 respectively. But here L1 = L2 = L (say) Then K = L+L/(L/K1 + L/K2) = 2K1K2K1+K2