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Q:

Two numbers x and y (x>y) such that their sum is equal to three times their difference. Then value of $$3xy\over 2(x^2-y^2$$ will be 

  • 1
    $$1{1\over 2} $$
  • 2
    $$1{1\over 3} $$
  • 3
    $$ {2\over 3}$$
  • 4
    1
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Answer : 4. " 1"

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