Simplification Questions with Solutions for Bank PO

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simplification questions with solutions

Simplification Questions with Solutions for Competitive Exams

Q.11. One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,50,000 as total savings, how much has he saved in Public Provident Fund ?

(A) Rs. 50,000

(B) Rs. 30,000

(C) Rs. 90,000

(D) Rs. 60,000


Ans .  D


Let savings in N.S.C and P.P.F. be Rs. x and Rs. (150000 - x) respectively. Then,

$$ {1\over3}x={1\over2}(150000-x) $$

  $$ → {x\over3} +{x\over2} = 75000 $$

  $$ → {5x\over6} = 75000 $$

  $$ → x ={75000×6\over3} = 90000 $$

Q.12. A man has Rs.480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has?

(A) 60

(B) 45

(C) 90

(D) 75


Ans .  C


Let number of notes of each denomination be x.

Then x + 5x + 10x = 480

→ 16x = 480

∴  x = 30.

Hence, total number of notes = 3x = 90.

Q.13. If a - b = 3 and a2 + b2 = 29, find the value of ab.

(A) 12

(B) 10

(C) 18

(D) 15


Ans .  B


2ab = (a2 + b2) - (a - b)2

= 29 - 9 = 20

ab = 10.

→ ab = 10.

Q.14. To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present?

(A) 35

(B) 10

(C) 58

(D) 62.5

(E) None of these


Ans .  D


Let the capacity of 1 bucket = x.

Then, the capacity of tank = 25x.

$$ New \ capacity \ of \ bucket \ =  {2\over5}x$$

  $$ ∴   \ Required \ number \ of \ buckets =   {25x\over{2x\over5}}$$

  $$ = \left(25x× {5x\over2} \right) $$

  $$ = {125\over2} = 62.5$$

Q.15. There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:

(A) 80

(B) 20

(C) 200

(D) 100


Ans .  D


Let the number of students in rooms A and B be x and y respectively.

Then, x - 10 = y + 10 → x - y = 20 .... (i)

and x + 20 = 2(y - 20) → x - 2y = -60 .... (ii)

Solving (i) and (ii) we get: x = 100, y = 80.

∴ The required answer A = 100.

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    Vikram Singh

    Providing knowledgable questions of Reasoning and Aptitude for the competitive exams.

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