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Welcome to our 'Percentage Questions with Answers' blog, your go-to resource for mastering the art of percentages! Whether you're a student preparing for exams or someone looking to enhance their numerical skills.
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Welcome to our Percentage Quiz Questions and Answers article! Whether you're a student preparing for exams, a professional brushing up on essential skills, or just someone who loves a good mental challenge, this Percentage Quiz Questions and Answers is designed for you.
Percentage aptitude questions are a common component of many competitive exams, job interviews, and academic assessments. These types of questions require candidates to calculate percentages, proportions, ratios, and other related concepts to solve problems
Percentage is a way of expressing a ratio in a mathematics subject. Also, percentage is very important in all competitive examinations, because other topics of mathematics also depend on percentage. Percent means per hundred (% = 1/100). Today in this article, I am providing percentage aptitude questions for all those students, who are preparing day-night.
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Don’t get stuck if you face difficulty in solving percentage questions, don't worry it happens. That time you just need to find percentage problems with solutions for bank exams or other competitive exams. So, here you can resolve your percentage problems with solutions for bank exams. With the help of these percentage problem solutions, you can improve...
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The sum of weights of A and B is 80 kg. 50% of A's weight is $${5\over6}$$ times the weight of B. Find the difference between their weights.
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Answer : 1 20 kg
Explanation :
Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.
Given:
- 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
- 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)
We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.
From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y
Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30
Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50
So, the weight of A is 50 kg and the weight of B is 30 kg.
Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20
Therefore, the difference between their weights is 20 kg.
The cost of an article was 75. The cost was first increased by 20% and later on it was reduced by 20%. The present cost of the article is:
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Answer : 1 72
If a number x is 10% less than another number y and y is 10% more than 125, then x is equal to-
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Answer : 4 123.75
A boy scored 125 marks and 140 marks in the first test and the second test respectively. If the maximum mark in each test is 150, then the percentage increase in his performance is ___________.
687 0 638f3e8bd319b37ca182cc82- 15%false
- 215%false
- 325%false
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Answer : 4 10%
In a school, if there are 36% boys and 352 girls, then the number of boys is ________.
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