10 years ago, respective ratio of the age of mother and daughter was 4 : 1. 10 years later, the respective ratio of the age of mother and daughter will become 2 : 1. At present, what is the sum of their age?

Five years ago the sum of the ages of A and B was 58 years. The difference between B's age 8 years ago and A's age 8 years hence is 16 years. The ratio of the present ages of A and B is:

In a school, $${3\over 8}$$ of the number of students are girls and the rest are boys. One-third of the number of boys are below 10 years and $${2\over 3}$$ of the number of girls are also below 10 years. If the number of students of age 10 or more years is 260, then the number of boys in the school is:

8 years ago, the average age of Rahul's family consisting of 6 members was 35 years. One year ago a new baby was born in this family. What will be the average age of the family four years hence?

If A's income is 3/5 times of B's income and C's income is 6/5 times of B's income then the ratio of C's income to A's income is -

Ram has 5 daughters. The average age of these 5 sisters is 28 years. The youngest one is 16 years old. What was the average age of the 4 daughters before the youngest one was born?

Ratio of age of father, mother and son is 9:8:3. Five years hence sum of their age will be 95 years. Find the age of son 5 years ago.

There are some friends, all less than 20 years. When paired amongst themselves they realize that the sum of their ages is a multiple of 5. If their ages are distinct prime numbers, then the number of possible pairs are: