Time and Distance problems with solutions for bank exams

Time and Distance Problems with Solutions for Competitive Exams

Q.11. A train travels at an average of 50 miles per hour for  hours and then travels at a speed of 70 miles per hours for  hours. How far did the train travel in the entire 4 hours?

$$ Solution $$

$$ Total\ distance\ travelled \ = \left(50× 2{1\over2} \right)+ \left(70× 1{1\over2} \right)$$

$$ miles \ = (125+125) \ miles = 230 \ miles  $$

Q.12. A man in a train notices that he can count 21 telephone posts in one minute. If they are known to be 50 metres apart, then at what speed is the train travelling?

$$ Solution $$

Number of gaps between 21 telephone posts = 20.

Distance travelled in 1 minute = (50 × 20) m = 1000 m = 1 km.

Q.13. Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree,   second after he see it strike the tree. How fair is the man from the wood chopper?

$$ Solution $$

$$Distance =\left(11× {11\over5} \right) feet = 2420 $$

Q.14. An express train travelled at an average speed of 100 km/ hr, stopping for 3 minutes after every 75 km. How long did it take to reach its destination 600 km form the starting point?

$$ Solution $$

$$Time \ taken \ to \ cover \ 600\  km = \left({600\over100} \right)hrs =6 hrs. $$

 $$ Number\ of \ stopagges = {600\over100}-1=7 $$

Total time of stoppages = (3 × 7) min = 21 min.

Hence, the total time taken = 6hrs 21 min.

Q.15. A certain distance is covered by a cyclist at a certain speed. If a jogger covers half the distance in double the time, the ratio of the speed of the jogger to that of the cyclist is :

$$ Solution $$

Let the distance covered by the cyclist be x and the time taken by y. $$ Then, Required \ ration = {{1\over2}\over2y}x : {x\over y} : = {1\over4} : 1 = 1 : 4$$

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