Aptitude Questions Practice Question and Answer

Q: A dishonest dealer professes to sell his good at cost price, but he uses a weight of 800 gm. For one kg. Find his gain percent? 1906 0

  • 1
    20
    Correct
    Wrong
  • 2
    25
    Correct
    Wrong
  • 3
    40
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
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Answer : 2. "25"

Q: The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ? 1872 1

  • 1
    14th element
    Correct
    Wrong
  • 2
    9th element
    Correct
    Wrong
  • 3
    12th element
    Correct
    Wrong
  • 4
    7th element
    Correct
    Wrong
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Answer : 3. "12th element"
Explanation :

Answer: C) 12th element Explanation: If we consider the third term to be ‘x”The 15th term will be (x + 12d)6th term will be (x + 3d)11th term will be (x + 8d) and 13th term will be (x + 10d).Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.x + 9d will be the 12th term. Thus, 12th term of the A.P will be zero.

Q: Length of a train is 300 metre. It’s speed is 72 km/hour. In how many seconds it can cross a pole? 1821 0

  • 1
    18 seconds
    Correct
    Wrong
  • 2
    15 seconds
    Correct
    Wrong
  • 3
    12 seconds
    Correct
    Wrong
  • 4
    20 seconds
    Correct
    Wrong
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Answer : 2. "15 seconds"

Q: The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ? 1808 1

  • 1
    42.2 mts
    Correct
    Wrong
  • 2
    33.45 mts
    Correct
    Wrong
  • 3
    66.6 mts
    Correct
    Wrong
  • 4
    58.78 mts
    Correct
    Wrong
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Answer : 3. "66.6 mts"
Explanation :

Answer: C) 66.6 mts Explanation: From above diagramAC represents the hill and DE represents the tower Given that AC = 100 m angleXAD = angleADB = 30° (∵ AX || BD ) angleXAE = angleAEC = 60° (∵ AX || CE) Let DE = h Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1) tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)∵ BD = CE and Substitute the value of CE from equation 1 100/√3 = 100−h(√3) => h = 66.66 mts The height of the tower = 66.66 mts.

Q: A 250 metre long train crosses a pole in 15 seconds. What is its speed in km/hour? 1778 0

  • 1
    90
    Correct
    Wrong
  • 2
    45
    Correct
    Wrong
  • 3
    70
    Correct
    Wrong
  • 4
    None of these
    Correct
    Wrong
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Answer : 4. "None of these"

Q: Find value of log27 +log 8 +log1000log 120 1721 1

  • 1
    1/2
    Correct
    Wrong
  • 2
    3/2
    Correct
    Wrong
  • 3
    2
    Correct
    Wrong
  • 4
    2/3
    Correct
    Wrong
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Answer : 2. "3/2"
Explanation :

Answer: B) 3/2 Explanation:  = log 33 + log 23+ log 103log10×3×22        =log33 12+log 23+log 10312log(10×3×22)                 =12log 33+3 log 2+12 log103log10+log3+log22                 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32

Q: The simple interest on a sum of money is $${4\over 9}$$of the principal and the number of years is equal to the rate percent per annum. The rate per annum is : 1715 0

  • 1
    5%
    Correct
    Wrong
  • 2
    $$6{2\over3}\%$$
    Correct
    Wrong
  • 3
    6%
    Correct
    Wrong
  • 4
    $$7{1\over5}\%$$
    Correct
    Wrong
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Answer : 2. "$$6{2\over3}\%$$"

Q: A shopkeeper earns a profit of shopkeeper earns a profit of 25% after giving a discount of 20%. Find the ratio between the cost price and the marked price. 1714 1

  • 1
    25:16
    Correct
    Wrong
  • 2
    16:25
    Correct
    Wrong
  • 3
    16:27
    Correct
    Wrong
  • 4
    27:10
    Correct
    Wrong
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Answer : 2. "16:25"

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