Aptitude Questions Practice Question and Answer

Q: 30 Men can complete a work in 25 days. In how many days can 75 men complete it? 4513 2

  • 1
    15
    Correct
    Wrong
  • 2
    12
    Correct
    Wrong
  • 3
    16
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
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Answer : 4. "10"

Q: The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ? 1853 1

  • 1
    14th element
    Correct
    Wrong
  • 2
    9th element
    Correct
    Wrong
  • 3
    12th element
    Correct
    Wrong
  • 4
    7th element
    Correct
    Wrong
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Answer : 3. "12th element"
Explanation :

Answer: C) 12th element Explanation: If we consider the third term to be ‘x”The 15th term will be (x + 12d)6th term will be (x + 3d)11th term will be (x + 8d) and 13th term will be (x + 10d).Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.x + 9d will be the 12th term. Thus, 12th term of the A.P will be zero.

Q: Cost price of 21 objects is equal to selling price of 15 objects. What is the profit? 4935 0

  • 1
    25%
    Correct
    Wrong
  • 2
    30%
    Correct
    Wrong
  • 3
    33%
    Correct
    Wrong
  • 4
    40%
    Correct
    Wrong
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Answer : 4. "40%"

Q: A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ? 3412 0

  • 1
    1080 cm
    Correct
    Wrong
  • 2
    180 m
    Correct
    Wrong
  • 3
    108 m
    Correct
    Wrong
  • 4
    118 cm
    Correct
    Wrong
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Answer : 3. "108 m"
Explanation :

Answer: C) 108 m Explanation: We know the rule that,   At particular time for all object , ratio of height and shadow are same.   Let the height of the pole be 'H'   Then  188=H48   => H = 108 m.

Q: Solve the equation 122x+1 = 1 ? 4083 0

  • 1
    -1/2
    Correct
    Wrong
  • 2
    1/2
    Correct
    Wrong
  • 3
    1
    Correct
    Wrong
  • 4
    -1
    Correct
    Wrong
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Answer : 1. "-1/2"
Explanation :

Answer: A) -1/2 Explanation: Rewrite equation as 122x+1 = 120   Leads to 2x + 1 = 0    Solve for x : x = -1/2

Q: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 2424 0

  • 1
    18
    Correct
    Wrong
  • 2
    14
    Correct
    Wrong
  • 3
    22
    Correct
    Wrong
  • 4
    24
    Correct
    Wrong
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Answer : 2. "14"
Explanation :

Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14

Q: What is the number of digits in 333? Given that log3 = 0.47712? 5528 0

  • 1
    12
    Correct
    Wrong
  • 2
    13
    Correct
    Wrong
  • 3
    14
    Correct
    Wrong
  • 4
    15
    Correct
    Wrong
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Answer : 2. "13"
Explanation :

Answer: B) 13 Explanation:  Let   Let x=333 = 333    Then, logx = 33 log3     = 27 x 0.47712 = 12.88224    Since the characteristic in the resultant value of log x is 12   ∴The number of digits in x is (12 + 1) = 13    Hence the required number of digits in 333is 13.

Q: On selling oranges 5 for Rs.1. One gets 20% profit. How many orange were purchased for Rs.1. 3869 0

  • 1
    3
    Correct
    Wrong
  • 2
    7
    Correct
    Wrong
  • 3
    4
    Correct
    Wrong
  • 4
    6
    Correct
    Wrong
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Answer : 4. "6"

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