CAT Practice Question and Answer

Q: A Woman’s downstream swimming rate is thrice of her upstream swimming rate. If she covers 12 km upstream in 2.5 hours, what distance she will cover in 5 hours downstream? 2994 0

  • 1
    72 km
    Correct
    Wrong
  • 2
    36 km
    Correct
    Wrong
  • 3
    56 km
    Correct
    Wrong
  • 4
    42 km
    Correct
    Wrong
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Answer : 1. "72 km"
Explanation :

Answer: A) 72 km Explanation: Rate of her upstream = 12/2.5 = 4.8 km/hr Then, ATQ Rate of downstream = 4.8 x 3 = 14.4 km/hr   Hence, the distance she covers downstream in 5 hrs = 14.4 x 5 = 72 kms.

Q: A 300m race is held between two players running 3m/s and 5m/s in swimming pool of 50m long. how many times the two player meet in opposite direction till the faster one completes the race ? 2993 0

  • 1
    3 times
    Correct
    Wrong
  • 2
    4 times
    Correct
    Wrong
  • 3
    5 times
    Correct
    Wrong
  • 4
    2 times
    Correct
    Wrong
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Answer : 1. "3 times"
Explanation :

Answer: A) 3 times Explanation: Let us assume A is the faster and B is slower, A takes 10s to finish a lap of 50 m, B takes 17s(approx) to finish a lap of 50 m.So at 11th sec A starts his 2nd lap by the time B will be in between so that is the first time they will meet each other, at 21st sec A starts his 3rd lap by the time B will be coming back to finish his 2nd lap. So that is the second time they meet in opposite. Then at 31st sec A will start his 4th lap by the time B would not even finish 2nd lap as he take 34(2*17) sec to finish 2 laps. So at 35th sec B will start his 3rd lap by the time A will be coming back to finish his 4th lap in the half way so they will meet 3rd time. At 41st sec A will start its fifth lap by the time B will be going to finish 3rd lap in same direction. At 50th second both will complete A's 5th lap and B's 3rd lap. So they will start next lap(A's 6th and B's 4th) from the same point in same direction. And A will finish the race after completing 300m(6*50) total distance and then they wont meet opposite to each other. So totally they met 3 times in opposite direction.

Q: If the rate increases by 2%, the simple interest received on a sum of money increases by Rs. 108. If the time period is increased by 2 years, the simple interest on the same sum increases by Rs.180. The sum is ? 2981 0

  • 1
    Rs. 540
    Correct
    Wrong
  • 2
    Rs. 415
    Correct
    Wrong
  • 3
    Rs. 404
    Correct
    Wrong
  • 4
    Data is not sufficient
    Correct
    Wrong
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Answer : 4. "Data is not sufficient"
Explanation :

Answer: D) Data is not sufficient Explanation: Let the sum be Rs. p, rate be R% p.a. and time be T years. Then,  P×T×(R+2)100-P×T×R100=108  ⇒2PT= 10800  ...... (1)  And,   P×R×(T+2)100-P×R×T100=180   ⇒2PR = 18000 ......(2) Clearly, from (1) and (2), we cannot find the value of pSo, the data is not sufficient.

Q: The age of Sohail, Afzal and Bilal are 17,16 and 12 respectively. If the age of Aslam also included the average of the ages is increased by 5. What is the age of Aslam? 2978 0

  • 1
    32
    Correct
    Wrong
  • 2
    33
    Correct
    Wrong
  • 3
    34
    Correct
    Wrong
  • 4
    35
    Correct
    Wrong
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Answer : 4. "35"
Explanation :

Answer: D) 35 Explanation: Given S = 17 yrs A = 16 yrs B = 12 yrs Average = 17 + 16 + 12/3 = 15 yrs Given if Aslam added to them, their average increases by 5 => Average of 4 members = 20 Let the age of Aslam be 'x' Then,  17 + 16 + 12 + x /4 = 20 => x = 80 - 45 => x = 35.    Hence, the age of Aslam is 35 yrs.

Q: The study of Heavenly bodies is called 2972 0

  • 1
    Astronomy
    Correct
    Wrong
  • 2
    Astrology
    Correct
    Wrong
  • 3
    Astrophysics
    Correct
    Wrong
  • 4
    Astronautics
    Correct
    Wrong
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Answer : 1. "Astronomy"
Explanation :

Answer: A) Astronomy Explanation: Astronomy is the study of planets and heavenly bodies. Historically, astronomy has focused on observations of heavenly bodies. It is a close cousin to astrophysics. Succinctly put, astrophysics involves the study of the physics of astronomy and concentrates on the behavior, properties and motion of objects out there.

Q: When a women sells 20 articles for Rs. 160, there is 40% loss. How many articles should she sell for Rs. 240 in order to earn 20% profit ? 2970 0

  • 1
    16
    Correct
    Wrong
  • 2
    15
    Correct
    Wrong
  • 3
    17
    Correct
    Wrong
  • 4
    14
    Correct
    Wrong
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Answer : 2. "15"
Explanation :

Answer: B) 15 Explanation: Given when she sells at Rs. 160 for 20 articles, she get 40% loss.   Then, to get 20% profit selling at Rs. 240 for let 'P' articles   => 1602060=240p120   => 120 x 160 x P = 20 x 70 x 240   => P =  15 articles.

Q: Select the correct statement about cellular respiration? 2965 0

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    All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule
    Correct
    Wrong
  • 2
    All the carbon atoms in glucose ultimately incorporated during cellular respiration into NADH molecule
    Correct
    Wrong
  • 3
    All the carbon atoms in glucose ultimately incorporated during cellular respiration into ATP molecule
    Correct
    Wrong
  • 4
    All the carbon atoms in glucose ultimately incorporated during cellular respiration into water molecule
    Correct
    Wrong
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Answer : 1. "All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule"
Explanation :

Answer: A) All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule Explanation: All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecules.

Q: The average weight of a group of boys is 30 kg. After a boy of weight 35 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ? 2962 0

  • 1
    6
    Correct
    Wrong
  • 2
    8
    Correct
    Wrong
  • 3
    4
    Correct
    Wrong
  • 4
    5
    Correct
    Wrong
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Answer : 3. "4"
Explanation :

Answer: C) 4 Explanation: Let the number of boys in the group originally be x.Total weight of the boys = 30xAfter the boy weighing 35 kg joins the group, total weight of boys = 30x + 35So 30x + 35 + 31(x + 1) = > x = 4.

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