CAT Practice Question and Answer
8Q: Contour bunding is a method of soil conservation used in 2937 05b5cc68be4d2b4197774c37b
5b5cc68be4d2b4197774c37b- 1Scrublands, liable to spread of weed growthfalse
- 2Hilly and Slopy or mountain areastrue
- 3Low flat plains, close to stream courses, liable to floodingfalse
- 4Desert margins, liable to strong wind actionfalse
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Answer : 2. "Hilly and Slopy or mountain areas"
Explanation :
Answer: B) Hilly and Slopy or mountain areas Explanation: Contour bunding is a proven sustainable land management practice for mountainous areas, marginal, sloping, and hilly land where the soil productivity is very low. It is widely adopted by the ethnic minorities of Nepal who practice the shifting cultivation system of farming.
Q: When combining with nonmetallic atoms, metallic atoms generally will 2936 05b5cc64ae4d2b4197774bc11
5b5cc64ae4d2b4197774bc11- 1Lose electrons and forms cationstrue
- 2Gain electrons and forms anionsfalse
- 3Lose electrons and forms anionsfalse
- 4Gain electrons and forms cationsfalse
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Answer : 1. "Lose electrons and forms cations"
Explanation :
Answer: A) Lose electrons and forms cations Explanation: When combining with nonmetallic atoms, metallic atoms generally will Lose electrons and forms cations. As the ionization energy of te metals are very low, so they can easily lose electrons and form positively charged ion called cations.
Q: There are several peacocks and deers in a cage (with no other types of animals). There are 72 heads and 200 feet inside the cage. How many peacocks are there, and how many deers ? 2935 05b5cc73de4d2b4197774f95d
5b5cc73de4d2b4197774f95d- 142 & 24false
- 238 & 26false
- 336 & 24false
- 444 & 28true
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Answer : 4. "44 & 28"
Explanation :
Answer: D) 44 & 28 Explanation: Letx = peacocks y = deers 2x + 4y = 200 x + y = 72 y = 72 - x 2x + 288 - 4x = 200 x = 44 peacocks y = 28 deers
Q: Three taps P, Q and R can fill a tank in 12 hrs, 15 hrs and 20 hrs respectively. If P is open all the time and Q and R are open for one hour each alternately, starting with Q, then the tank will be full in how many hours ? 2935 05b5cc6c0e4d2b4197774dafb
5b5cc6c0e4d2b4197774dafb- 19 hrsfalse
- 27 hrstrue
- 313 hrsfalse
- 411 hrsfalse
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Answer : 2. "7 hrs"
Explanation :
Answer: B) 7 hrs Explanation: Given, P can fill in 12 hrs Q can fill in 15 hrs R can fill in 20 hrs => Volume of tank = LCM of 12, 15, 20 = 60 lit => P alone can fill the tank in 60/12 = 5 hrs => Q alone can fill the tank in 60/15 = 4 hrs => R alone can fill the tank in 60/20 = 3 hrs Tank can be filled in the way that (P+Q) + (P+R) + (P+Q) + (P+R) + .... => Tank filled in 2 hrs = (5+4) + (5+3) = 9 + 8 = 17 lit => In 6 hrs = 17 x 6/2 = 51 lit => In 7th hr = 51 + (5+4) = 51 + 9 = 60 lit => So, total tank will be filled in 7 hrs.
Q: k, l, m together started a business. k invested Rs.6000 for 5 months l invested Rs.3600 for 6 months and m Rs.7500 for 3 months. If they get a total profit of Rs.7410. Find the share of l ? 2934 05b5cc6dce4d2b4197774e9a6
5b5cc6dce4d2b4197774e9a6- 1Rs. 1640false
- 2Rs. 2500false
- 3Rs. 2160true
- 4Rs. 3000false
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Answer : 3. "Rs. 2160"
Explanation :
Answer: C) Rs. 2160 Explanation: => 60x5 : 36x6 : 75x3 => 100 : 72 : 75 => 72/247 x 7410 = Rs. 2160
Q: Sponge is to Porous as Rubber is to 2927 05b5cc6abe4d2b4197774d006
5b5cc6abe4d2b4197774d006- 1Inflexiblefalse
- 2Elastictrue
- 3Solidfalse
- 4Massivefalse
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Answer : 2. "Elastic"
Explanation :
Answer: B) Elastic Explanation: A sponge is a porous material. Rubber is an elastic material. Since Rubber is not a Massive or solid and not an inflexible thing, it is elastic.
Q: Which is not a sediment transporting agent? 2927 05b5cc66de4d2b4197774bfa5
5b5cc66de4d2b4197774bfa5- 1Stratificationtrue
- 2Windstormsfalse
- 3Glacial Icefalse
- 4Stream waterfalse
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Answer : 1. "Stratification"
Explanation :
Answer: A) Stratification Explanation: Stratification as actually the settling down of sediments with different properties to form layers/strata over years. Stratification especially occurs on the bed of water bodies such as oceans. Stratified sedimentary rocks are used to study the ecological conditions over previous years/eras. The other choices like Windstorms, Glacial Ice and Stream water are mediums which sediments are transported.
Q: A merchant buys two items for Rs. 7500. One item he sells at a profit of 16% and the other item at 14% loss. In the deal, the merchant makes neither any profit nor any loss. What is the difference between the selling price of both the items? 2922 05b5cc69de4d2b4197774c88d
5b5cc69de4d2b4197774c88d- 1Rs. 620true
- 2Rs. 654false
- 3Rs. 725false
- 4Rs. 747false
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Answer : 1. "Rs. 620"
Explanation :
Answer: A) Rs. 620 Explanation: Let the C.P of one item is Rs. P and that of other is Rs. (7500 - P) According to the data given C.P = S.P => Px(116/100) + (7500-P)x(86/100) = 7500 => 30P = 105000 => P = 3500 Required difference between selling prices = Rs. [(3500/100) x 116] - [(4000/100) x 86] = 4060-3440 = Rs. 620