GATE Practice Question and Answer
8Q: Taps X and Y can fill a tank in 30 and 40 minutes respectively.Tap Z can empty the filled tank in 60 minutes.If all the three taps are kept open for one minute each,how much time will the taps take to fill the tank? 5781 05b5cc764e4d2b4197774fde1
5b5cc764e4d2b4197774fde1- 148minfalse
- 272minfalse
- 324mintrue
- 4None of thesefalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "24min"
Explanation :
Answer: C) 24min Explanation: Given taps X and Y can fill the tank in 30 and 40 minutes respectively. Therefore, part filled by tap X in 1 minute = 1/30 part filled by tap Y in 1 minute = 1/40 Tap Z can empty the tank in 60 minutes. Therefore, part emptied by tap Z in 1 minute = 1/60 Net part filled by Pipes X,Y,Z together in 1 minute = [1/30 +1/40 - 1/60] = 5/120 = 1/24 i.e., the tank can be filled in 24 minutes.
Q: What should be replaced in the place of '?' in the following series ? QAR, RAS, SAT, TAU, ? 1049 05b5cc764e4d2b4197774fda8
5b5cc764e4d2b4197774fda8- 1UATfalse
- 2UAVtrue
- 3UASfalse
- 4UTSfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "UAV"
Explanation :
Answer: B) UAV Explanation: In this series, the third letter is repeated as the first letter of the next segment. The middle letter, A, remains static. The third letters are in alphabetical order, beginning with R.
Q: Two stations A and B are 200 km apart on a straight track. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet? 1366 05b5cc764e4d2b4197774fdad
5b5cc764e4d2b4197774fdad- 112 a.m.false
- 21 p.m.false
- 311 a.m.false
- 412 p.m.true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "12 p.m."
Explanation :
Answer: D) 12 p.m. Explanation: Assume both trains meet after 'p' hours after 7 a.m.Distance covered by train starting from A in 'p' hours = 20p kmDistance covered by train starting from B in (p-1) hours = 25(p-1)Total distance = 200=> 20x + 25(x-1) = 200=> 45x = 225=> p= 5Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.
Q: What should be replaced in the place of '?' in the following series ? JAK, KBL, LCM, MDN, ? 1144 05b5cc764e4d2b4197774fd9e
5b5cc764e4d2b4197774fd9e- 1MENfalse
- 2NEMfalse
- 3NEOtrue
- 4OEPfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "NEO"
Explanation :
Answer: C) NEO Explanation: This is an alternating series in alphabetical order. The middle letters follow the order ABCDE. The first and third letters are alphabetical beginning with J. The third letter is repeated as a first letter in each subsequent three-letter segment.
Q: A Bus travels first half distance between two places with a speed of 40 kmph and the rest half distance with a speed of 60 kmph. The average speed of the Bus is ? 967 05b5cc764e4d2b4197774fda3
5b5cc764e4d2b4197774fda3- 148 kmphtrue
- 250 kmphfalse
- 346 kmphfalse
- 442 kmphfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "48 kmph"
Explanation :
Answer: A) 48 kmph Explanation: we know that speed = distance traveled/time takenlet the total distance traveled by the car is 2x km.then time taken by it to cover first half is x/60 hour.and for second half is x/40 hour.Then average speed= total distance travelled / total time taken. i.e. 2xx60+x40 => 2x5x120 = 48 kmph.
Q: A train travels 325 km in 3.5 hours and 470 km in 4 hours. Find the average speed of train ? 1057 05b5cc764e4d2b4197774fd99
5b5cc764e4d2b4197774fd99- 1107 kmphfalse
- 2106 kmphtrue
- 372 kmphfalse
- 476 kmphfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "106 kmph"
Explanation :
Answer: B) 106 kmph Explanation: As we know that Speed = Distance / Timefor average speed = Total Distance / Total Time TakenThus, Total Distance = 325 + 470 = 795 kmThus, Total Speed = 7.5 hrsAverage Speed = 795/7.5 => 106 kmph.
Q: Statement: Air export volumes have increased substantially over the past decade causing backlogs and difficulties for air cargo agents because of increased demand for space and service.Courses of action:a. Airlines and air cargo agents should jointly work out a solution to combat the problem.b. The reasons for the increase in the volume of air exports should be found out. 1407 05b5cc764e4d2b4197774fd94
5b5cc764e4d2b4197774fd94- 1Only a followstrue
- 2Both a and b followsfalse
- 3Only b followsfalse
- 4Neither a nor b followsfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "Only a follows"
Explanation :
Answer: A) Only a follows Explanation: The problem faced, by the airlines and cargo agents is the non availability of cargo space. Therefore, right course of action is to combat the problem.
Q: A man walks 6 km at a speed of 112kmph, runs 8 km at a speed of 2 kmph and goes by bus another 32 km. Speed of the bus is 8 kmph. Find the average speed of the man in kmph. 1794 05b5cc764e4d2b4197774fd8a
5b5cc764e4d2b4197774fd8a- 14314false
- 24213true
- 32413false
- 43414false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "4213"
Explanation :
Answer: B) Option B Explanation: Man walked 6 km at 1.5 kmph, again he walked 8 km at speed of 2 kmph and 40 km at a speed of 8kmphtime taken indivisually: => 6/1.5 = 4 m=> 8/2 = 4 m=> 40/8 = 5 m Average speed of man= total distance/ total time=> 54/13 = 4213 kmph