Answer: D) None of the above Explanation: 504/M = 384/800 (504 x 800) / 384 = M M = 1050

Answer: B) 76.92% Explanation: Let the milk he bought is 1000 ml Let C.P of 1000 ml is Rs. 100 Here let he is mixing K ml of water He is getting 30% profit => Now, the selling price is also Rs. 100 for 1000 ml => 100 : K% = 100 : 30 10 : 3 is ratio of milk to water => Percentage of milk = 10 x 100/13 = 1000/13 = 76.92%

Answer: A) 21 min Explanation: Let the pipe B be closed after 'K' minutes. 30/16 - K/24 = 1 => K/24 = 30/16 - 1 = 14/16 => K = 14/16 x 24 = 21 min.

Answer: C) 15 days Explanation: We know that Time is inversely proportional to Efficiency Here given time ratio of P & P+Q as P/P+Q = 150/100 = 3:2 Efficiency ratio of P & Q as P:Q = 2:1 ....(1) Given Efficiency ratio of Q & R as Q:R = 3:1 ....(2) From (1) & (2), we get P:Q:R = 6:3:1 P alone can finish the work in 22.5(3+1)/6 = 15 days.

Answer: C) Both A & B gives result Explanation: a and b give, profit after 3 years = Rs.(3/8 x 22000) = Rs.8250. From c also, profit after 3 years = Rs. (2750 x 3) = Rs. 8250. ∴ P's share = Rs.(8250 x 5/11) = Rs. 3750. Thus, (either C is redundant) or (a and b are redundant).

Answer: D) Rs. 1250 Explanation: 2500 in 5th year and 3000 in 7th year So in between 2 years Rs. 500 is increased => for a year 500/2 = 250So, per year it is increasing Rs.250 then in 5 years => 250 x 5 = 1250Hence, the initial amount must be 2500 - 1250 = Rs. 1250

Answer: B) J, L Explanation: This question concerns a committee’s decision about which five of eight areas of expenditure to reduce. The question requires you to suppose that K and N are among the areas that are to be reduced, and then to determine which pair of areas could not also be among the five areas that are reduced. The fourth condition given in the passage on which this question is based requires that exactly two of K, N, and J are reduced. Since the question asks us to suppose that both K and N are reduced, we know that J must not be reduced: Reduced         ::      K, NNot reduced   ::      J The second condition requires that if L is reduced, neither N nor O is reduced. So L and N cannot both be reduced. Here, since N is reduced, we know that L cannot be. Thus, adding this to what we’ve determined so far, we know that J and L are a pair of areas that cannot both be reduced if both K and N are reduced: Reduced        ::      K, NNot reduced  ::      J, L Answer choice (B) is therefore the correct answer.

1. Answer : 2 Explanation : Productivity = Total production/area of Agr.land  Productivity of UP = [ (35000+30000+25000) / (30/100) ] = 300000   Productivity of MP = [ (30000+37500+27500) / (25/100) ] = 380000   Productivity of Bihar = [ (22500+27500+25000) / (20/100) ] = 375000  Productivity of Odisha = [ (22500+15000+10000) / (5/100) ]= 950000   Productivity of Haryana = [ (30000+25000+35000) / (8/100) ] = 1125000   Productivity of Punjab = [ (40000+35000+30000) / (12/100) ] = 875000  The Productivity of Haryana is the maximum.       2. Answer : 5   Explanation : Production of Punjab is maximum = 105000 tonnes      3. Answer : 3  Explanation : Production of Wheat in Punjab = 40000 tones Production of Maize in Odisha = 10000 tones Required % = (40000 - 10000)/100 = 300%      4. Answer : 4  Explanation : The ratio of prodution of Rice in Bihar to the production of Wheat in Haryana = 25000 tonnes : 25000 tonnes = 1 : 1       5. Answer : 1   Explanation : Income of MP from export of 40% of Rice at the rate of Rs.30 per kg = Rs.39crore Income of UP from export of 30% of Rice at the rate of Rs.32 per kg = Rs.28.8 crore  Required ratio = 39 : 28.8 = 390 : 288 = 65 : 48