Answer: C) 80% Explanation: circumference of A = 2πr = 8 => so r = 4πvolume = π×4π2×10 = 160πcircumference of B = 2πr   = 10 => so r = 5πvolume = π×5π2×8 =  200πso ratio of capacities = 160/200 = 0.8 so capacity of A will be 80% of the capacity of B.

Answer: D) -1 Explanation: 3, 7, 6, 5, 9, 3, 12, 1, 15, ... has two different series 1) 3, 6, 9, 12, 15..... 2) 7, 5, 3, 1, ..... -1 is the next number.

Answer: B) 30 Explanation: Here given 120 men = 200 children therefore 1 child = 3/5 of Man------ step I Now given that the food was consumed by 150 children From step I we get 150 children =90 Men ( 1 child = 3/5 Man ie , 150 X 3/5 = 90)So the food is for (120-90) men = 30 Men

Answer: A) Rs. 404.80 Explanation: Let C1 be the cost price of the first article and C2 be the cost price of the second article.Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%. We know, C1 + C2 = 600.The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2. The total selling price of the first and second article = 1.22C1 + 0.92C2. As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2. Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get1.22C1 + 0.92(600 - C1) = 600or 1.22C1 - 0.92C1 = 600 - 0.92*600or 0.3C1 = 0.08*600 = 48or C1 = 48/(0.3) = 160.If C1 = 160, then C2 = 600 - 160 = 440.The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.

Answer: B) 14 men Explanation: M x T / W = Constantwhere, M= Men (no. of men)T= Time takenW= Work loadSo, here we applyM1 x T1/ W1 = M2 x T2 / W2Given that, M1 = 4 men, T1 = 7 hours ; T2 = 2 hours, we have to find M2 =?Note that here, W1 = W2 = 1 road, ie. equal work load.Clearly, substituting in the above equation we get, M2 = 14 men.

Answer: A) Rs. 1,44,750 Explanation: 3T+12C = 48,250----(1) 21T+36C = ? multiply eq (1) with 3i.e,, 3(7T+12C) = 48,250*321T+36C = 1,44,750/-

Answer: C) Rs. 2160 Explanation: End of first year     :  10000 x (3/5) = Rs. 6000End of second year :  6000 x (3/5) = Rs. 3600End of third year    :  3600 x (3/5) = Rs. 2160

Answer: B) 1024 Explanation: Fruits reduced by 1/4.Total no. of bags N = 5Formula to find no. of fruits in 1st bag = 4^nLast Bag = 4 fruits.That means, 4th bag = 4 x 4 = 16 fruits3rd bag = 16 x 4 = 64 fruits2nd bag = 64 x 4 = 256 fruits1st bag = 256 x 4= 1024 fruits.