GATE Practice Question and Answer
8Q: Read the following puzzle carefully, answer the question asked below ? Seven person K, L, M, N, O, P & Q likes seven colours. Yellow, White, Red, Orange, Blue, Gray and Black. They visit in different days starting from Monday to Sunday. 1) K visits one day after Thursday. 2) Only 4 people are in between K and L 3) The one who likes Red colour visits immediately after L. 4) Only one person visit between Red and Blue 5) The one who like white colour visit before one of days on which day M visits 6) The one who like white colour does not visit on Monday. 7) Only 1 person is in between N and O. N like Yellow. 8) There are same as many person in between K and Blue colour which are one less in between L and M. 9) Neither Q nor P likes Black. 10) Q does not visit on Saturday and does not like grey colour. Question : Who visits on Sunday and Tuesday and their favourite colors ? 2040 15b5cc6c2e4d2b4197774dba0
5b5cc6c2e4d2b4197774dba0- 1P & Mfalse
- 2N & Kfalse
- 3K & Ltrue
- 4P & Qfalse
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Answer : 3. "K & L"
Explanation :
Answer: C) K & L Explanation: Monday - N - Yellow Tuesday - L - White Wednesday - O - Red Thursday - Q - Orange Friday - M - Blue Saturday - P - Grey Sunday - K - Black From the above table, K & L visits Sunday & Tuesday and their favourite colors are Black and white respectively.
Q: 82.5% of 2360? 2036 05b5cc60ae4d2b4197774b5a1
5b5cc60ae4d2b4197774b5a1- 11960false
- 21954false
- 31947true
- 41931false
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Answer : 3. "1947"
Explanation :
Answer: C) 1947 Explanation: Given 82.5% of 2360 82.5100 x 2360 = 0.825 x 2360 = 1947
Q: In a hostel, there was food for 1000 students for one month. After 10 days, 1000 more students joined the hostel. How long would the students be able to carry on with the remaining food? 2034 05b5cc774e4d2b41977750025
5b5cc774e4d2b41977750025- 110 daystrue
- 215 daysfalse
- 320 daysfalse
- 45 daysfalse
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Answer : 1. "10 days"
Explanation :
Answer: A) 10 days Explanation: After 10 days, the remaining food would be sufficient for the 1000 students for 20 more days -->If 1000 more students are added, it shall be sufficient for only 10 days (as the no. of students is doubled, the days are halved).
Q: FRIEND : FPIBNZ :: PATRON : ? 2033 05b5cc6b1e4d2b4197774d2fe
5b5cc6b1e4d2b4197774d2fe- 1PTYOPIfalse
- 2PYTOPJfalse
- 3PYTOOJtrue
- 4PYTPOJfalse
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Answer : 3. "PYTOOJ"
Explanation :
Answer: C) PYTOOJ Explanation: FRIEND : FPIBNZ Follows a pattern that, F - F R- second letter to left of R i.e, P I - I E - Third letter to left of E i.e, B N - N D - Fourth letter to left of D i.e, Z Similarly, for PATRON P - P A - second letter to left of A i.e, Y T - T R - Third letter to left of R i.e, O O - O N - Fourth letter to left of N i.e, J PATRON : PYTOOJ Therefore, FRIEND : FPIBNZ :: PATRON : PYTOOJ
Q: When a computer prints a report this output is called 2025 05b5cc69fe4d2b4197774ca14
5b5cc69fe4d2b4197774ca14- 1Soft copyfalse
- 2Hard copytrue
- 3Printingfalse
- 4Programfalse
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Answer : 2. "Hard copy"
Explanation :
Answer: B) Hard copy Explanation: Hard copy is the output which is printed by the computer.
Q: A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ? 2025 05b5cc6f4e4d2b4197774f004
5b5cc6f4e4d2b4197774f004- 124 - 1false
- 22425-1false
- 3(24-1)(23-1)25true
- 4Nonefalse
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Answer : 3. "(24-1)(23-1)25"
Explanation :
Answer: C) C Explanation: It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects. Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection. Hence, we can select 1 black ball from 4 black ballsor 2 black balls from 4 black balls.or 3 black balls from 4 black balls.or 4 black balls from 4 black balls. Hence, number of ways in which we can select the black balls = 4C1 + 4C2 + 4C3 + 4C4= 24-1 ........(A) Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection. Hence, we can select 1 red ball from 3 red ballsor 2 red balls from 3 red ballsor 3 red balls from 3 red balls Hence, number of ways in which we can select the red balls= 3C1 + 3C2 + 3C3=23-1........(B) Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)or 1 blue ball from 5 blue ballsor 2 blue balls from 5 blue ballsor 3 blue balls from 5 blue ballsor 4 blue balls from 5 blue ballsor 5 blue balls from 5 blue balls. Hence, number of ways in which we can select the blue balls= 5C0 + 5C1 + 5C2 + … + 5C5= 25..............(C) From (A), (B) and (C), required number of ways= 2524-123-1
Q: A motorboat goes 8 km an hour in still water, but takes thrice as much time in going the same distance against the current than going with the current. Then find the speed of the current? 2023 05b5cc6ace4d2b4197774d09b
5b5cc6ace4d2b4197774d09b- 14 kmphtrue
- 26 kmphfalse
- 33 kmphfalse
- 42 kmphfalse
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Answer : 1. "4 kmph"
Explanation :
Answer: A) 4 kmph Explanation: Let the speed of current = 'C' km/hr Given the speed of boat in still water = 6 kmph Let 'd' kms be the distance it covers. According to the given data, Boat takes thrice as much time in going the same distance against the current than going with the current i.e, d8 - C = 3 × d8 + C ⇒ 24 - 3C = 8 + C⇒ 4C = 16⇒ C = 4 kmph Hence, the speed of the current C = 4 kmph.
Q: How many four digit even numbers can be formed using the digits {2, 7, 5, 3, 9, 1} ? 2023 05b5cc6d7e4d2b4197774e705
5b5cc6d7e4d2b4197774e705- 159false
- 260true
- 361false
- 464false
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Answer : 2. "60"
Explanation :
Answer: B) 60 Explanation: The given digits are 1, 2, 3, 5, 7, 9 A number is even when its units digit is even. Of the given digits, two is the only even digit.Units place is filled with only '2' and the remaining three places can be filled in ⁵P₃ ways. Number of even numbers = ⁵P₃ = 60.