GATE Practice Question and Answer
8Q: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3008 05b5cc6e5e4d2b4197774ed42
5b5cc6e5e4d2b4197774ed42- 1127.5 mtrue
- 2254 mfalse
- 3184 mfalse
- 4212 mfalse
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Answer : 1. "127.5 m"
Explanation :
Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.
Q: A can do a piece of work in 21 days and B in 28 days. Together they started the work and B left after 4 days. In how many days can A alone do the remaining work ? 1966 05b5cc6e5e4d2b4197774ed3d
5b5cc6e5e4d2b4197774ed3d- 114 daystrue
- 218 daysfalse
- 321 deaysfalse
- 416 daysfalse
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Answer : 1. "14 days"
Explanation :
Answer: A) 14 days Explanation: Let A worked for x days. x/21 + 4/28 = 1 => x = 18 A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.
Q: A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year ? 6189 05b5cc6e5e4d2b4197774ed38
5b5cc6e5e4d2b4197774ed38- 121:29false
- 241:54false
- 332:45true
- 437:51false
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Answer : 3. "32:45"
Explanation :
Answer: C) 32:45 Explanation: A : B(8000x4)+(4000x8) : (9000x6)+(6000x6) 64000 : 90000=> 32 : 45
Q: 9 men and 12 boys finish a job in 12 days, 12 men and 12 boys finish it in 10 days. 10 men and 10 boys shall finish it in how many days ? 9195 05b5cc6e5e4d2b4197774ed33
5b5cc6e5e4d2b4197774ed33- 115 daysfalse
- 211 daysfalse
- 314 daysfalse
- 412 daystrue
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Answer : 4. "12 days"
Explanation :
Answer: D) 12 days Explanation: 9M + 12B ----- 12 days ...........(1)12M + 12B ------- 10 days........(2)10M + 10B -------?108M + 144B = 120M +120B24B = 12M => 1M = 2B............(3) From (1) & (3) 18B + 12B = 30B ---- 12 days 20B + 10B = 30B -----? => 12 days.
Q: A cistern is normally filled in 8 hours but takes two hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in ? 1391 05b5cc6e5e4d2b4197774ed2e
5b5cc6e5e4d2b4197774ed2e- 120 hrstrue
- 228 hrsfalse
- 336 hrsfalse
- 440 hrsfalse
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Answer : 1. "20 hrs"
Explanation :
Answer: A) 20 hrs Explanation: 1/8 - 1/x = 1/10 => x = 40 hrs
Q: A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ? 1431 05b5cc6e5e4d2b4197774ed29
5b5cc6e5e4d2b4197774ed29- 125 secfalse
- 240 sectrue
- 338 secfalse
- 432 secfalse
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Answer : 2. "40 sec"
Explanation :
Answer: B) 40 sec Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.= 36 x 5/18 = 10 m/sec. Distance to be covered = 260 + 140 = 400 m. Time taken = 400/10 = 40 sec.
Q: What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high ? 1033 05b5cc6e5e4d2b4197774ed1f
5b5cc6e5e4d2b4197774ed1f- 113 mtrue
- 214 mfalse
- 315 mfalse
- 416 mfalse
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Answer : 1. "13 m"
Explanation :
Answer: A) 13 m Explanation: The length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is => d2 = 122 + 42 + 32 = 13mts.
Q: In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case ? 5929 05b5cc6e5e4d2b4197774ed24
5b5cc6e5e4d2b4197774ed24- 1693false
- 2741false
- 3528true
- 4654false
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Answer : 3. "528"
Explanation :
Answer: C) 528 Explanation: Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)= (1200)(30)(3) kg. Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k As the same provisions are available=> (1200)(30)(3) = (1200 + x)(25)(2.5) x = ([(1200)(30)(3)] / (25)(2.5)) - 1200 => x = 528.