GRE Practice Question and Answer
8Q: A farmer divides his herd of k cows among his 4 sons, so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 9 cows. Then k is equal to ? 1136 05b5cc73de4d2b4197774f92a
5b5cc73de4d2b4197774f92a- 1160false
- 2120false
- 3140false
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Answer : 4. "180"
Explanation :
Answer: D) 180 Explanation: Given total number of cows = kNow, 1st son share = k/22nd son share = k/43rd son share = k/54th son share = 9 (k) + (k/4) + (k/5) + 9 = k=> k - (19k/20) = 9=> (20k-19k)/20 = 9=> k = 180.
Q: If in the following set of numbers, the first and the third digits are interchanged in each number, which number will be second from the end if arranged in ascending order after interchanging the digits ? 585 546 514 404 206 369 1013 05b5cc73de4d2b4197774f92f
5b5cc73de4d2b4197774f92f- 1404false
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- 3415true
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Answer : 3. "415"
Explanation :
Answer: C) 415 Explanation: Given numbers are 585 546 514 404 206 369Then interchanging the 1st and 3rd digits of the given numbers, we get585 645 415 404 602 963Now, arranging them in ascending order963 645 602 585 415 404Then the last second number is 415.
Q: The ratio of present ages of X and Y is 4:5. Which of the following can't be the ratio of ages of X and Y, 20 years ago ? 1451 05b5cc73de4d2b4197774f925
5b5cc73de4d2b4197774f925- 12 : 5false
- 28 : 15false
- 39 : 10true
- 43 : 5false
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Answer : 3. "9 : 10"
Explanation :
Answer: C) 9 : 10 Explanation: The ratio of X and Y ages at present is 4:5. Then, the ratio 20 years ago will not be more than the ratio at present. So, from the options 9:10 is not satifying => its ratio is 0.9 which is greater than presnt ratio of 0.8.
Q: There are 3 sections with 5 questions each. If four questions are selected from each section, the chance of getting different questions is ? 828 05b5cc73de4d2b4197774f920
5b5cc73de4d2b4197774f920- 11000false
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Answer : 4. "125"
Explanation :
Answer: D) 125 Explanation: Methods for selecting 4 questions out of 5 in the first section = 5 x 4 x 3 x 2 x 1/4 x 3 x 2 x 1 = 5. Similarly for other 2 sections also i.e 5 and 5 So total methods = 5 x 5 x 5 = 125.
Q: Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ? 3816 05b5cc73de4d2b4197774f91b
5b5cc73de4d2b4197774f91b- 110true
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Answer : 1. "10"
Explanation :
Answer: A) 10 Explanation: Given total rupees = 20 RsNo. of one rupee stamps = 3Now, remaining money = Rs. 17With that he buys only 2 and 5 rupee stampsLet number of Rs. 5 stamps = KLet number of Rs. 2 stamps = L5K + 2L = 17K = 3, L = 1 (possible)L = 6, K = 1 (possible)=> But given that they are different in number so, K is not equal to 3one rupee stamps = 32 two stamps = 65 rupee stamps = 1Total number of stamps = 10.
Q: An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ? 1492 05b5cc73de4d2b4197774f911
5b5cc73de4d2b4197774f911- 121.4 and 42.8false
- 225.2 and 50.4false
- 331.4208 and 62.8416true
- 433.12 and 66.24false
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Answer : 3. "31.4208 and 62.8416"
Explanation :
Answer: C) 31.4208 and 62.8416 Explanation: Birds speeds in mtrs/sec is 'x' and '2x' .While flying from Engine to end, relative speed = (x+10) m/secfrom end to engine, flying speed = (2x - 10) mtr/secso 1000/(x+10) + 1000/(2x-10) = 187.5 secssolving it, we getso x = 8.728 m/sec and 2x= 17.456 m/sec x = 31.4208 km/hr and 2x = 62.8416 km/hr.
Q: There are 15 lines in plane. How many intersections (Maximum) can be made ? 1442 05b5cc73de4d2b4197774f916
5b5cc73de4d2b4197774f916- 155false
- 2105true
- 3215false
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Answer : 2. "105"
Explanation :
Answer: B) 105 Explanation: First line will cut all other 14, similarly second will cut 13, and so onTotal = 14+13+12+11+10+9+8+7+6+5+4+3+2+1 = 105.
Q: Hemavathi gets 3 marks for each right sum and loses 2 marks for each wrong sum. He attempts 35 sums and obtains 60 marks. The number of sums attempted correctly is ? 1111 05b5cc73de4d2b4197774f90c
5b5cc73de4d2b4197774f90c- 123false
- 224false
- 325false
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Answer : 4. "26"
Explanation :
Answer: D) 26 Explanation: Let, Hema attempted 'k' sum correctly, then k x 3 -2 x(35-k) = 605k = 130k = 26 so 26 correct sums.