IIT JEE Practice Question and Answer
8Q: A sweet seller sells 3/5th part of sweets at a profit of 10% and remaining at a loss of 5%. If the total profit is Rs 1500, then what is the total cost price of sweets ? 6091 05b5cc75ee4d2b4197774fc93
5b5cc75ee4d2b4197774fc93- 1Rs.37,500true
- 2Rs.36,400false
- 3Rs.37,415false
- 4Rs.36,500false
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Answer : 1. "Rs.37,500"
Explanation :
Answer: A) Rs.37,500 Explanation: Assume A be the cost price. Therefore,35×A×10100 - 25×A×5100 = 1500 => A = Rs 37,500.
Q: A web page is located using a 6059 05b5cc639e4d2b4197774baa5
5b5cc639e4d2b4197774baa5- 1Universal Record Locatorfalse
- 2Universal Resource Locatortrue
- 3Uniform Record Linkingfalse
- 4Universal Record Linkingfalse
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Answer : 2. "Universal Resource Locator"
Explanation :
Answer: B) Universal Resource Locator Explanation: A web page is located using a URL (Universal Resource Locator). Universal Resource Locator is also known as web address. It basically refers to a web resource which is meant for the specification of its location on the network of computer. It is also a mechanism through which information can be retrieved.
Q: What bet can never be won? 6022 05b5cc61ee4d2b4197774b769
5b5cc61ee4d2b4197774b769- Show AnswerHide Answer
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Answer :
Explanation :
ALPHABET is the bet can never be won.
Q: In a fort, there are 1200 soldiers. If each soldier consumes 3 kg per day, the provisions available in the fort will last for 30 days. If some more soldiers join, the provisions available will last for 25 days given each soldier consumes 2.5 kg per day. Find the number of soldiers joining the fort in that case ? 5924 05b5cc6e5e4d2b4197774ed24
5b5cc6e5e4d2b4197774ed24- 1693false
- 2741false
- 3528true
- 4654false
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Answer : 3. "528"
Explanation :
Answer: C) 528 Explanation: Assume x soldiers join the fort. 1200 soldiers have provision for 1200 (days for which provisions last them)(rate of consumption of each soldier)= (1200)(30)(3) kg. Also provisions available for (1200 + x) soldiers is (1200 + x)(25)(2.5) k As the same provisions are available=> (1200)(30)(3) = (1200 + x)(25)(2.5) x = ([(1200)(30)(3)] / (25)(2.5)) - 1200 => x = 528.
Q: How many times can you subtract 10 from 100? 5890 05b5cc669e4d2b4197774bf5e
5b5cc669e4d2b4197774bf5e- 19 timesfalse
- 210 timesfalse
- 31 timetrue
- 40 timesfalse
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Answer : 3. "1 time"
Explanation :
Answer: C) 1 time Explanation: How many times can you subtract 10 from 100, for this if we go through logically, it is only 1 time. For the first time if we subtract 10 from 100, then there will no 100 to subtract from. Hence, it is only 1 time we can subtract 10 from 100.
Q: The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of ? 5889 05b5cc6e0e4d2b4197774eb98
5b5cc6e0e4d2b4197774eb98- 14:5false
- 26:5true
- 33:2false
- 41:3false
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Answer : 2. "6:5"
Explanation :
Answer: B) 6:5 Explanation: 4:5 3:2 -------=> 12:15:10 12:10 => 6:5
Q: 64 boys and 40 girls form a group for social work. During their membership drive, the same number of boys and girls joined the group. How many members does the group have now, if the ratio of boys to girls is 4:3 ? 5887 05b5cc6ebe4d2b4197774ee7d
5b5cc6ebe4d2b4197774ee7d- 1168true
- 2201false
- 3147false
- 4154false
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Answer : 1. "168"
Explanation :
Answer: A) 168 Explanation: Let us say x boys and x girls joined the group. (64 + x)/(40 + x) = 4/3 192 + 3x = 160 + 4x => x = 32 Number of members in the group = 64 + x + 40 + x = 104 + 2x = 168.
Q: If 78K928L is divisible by 6, then which of the following can Q and R take ? 5887 05b5cc741e4d2b4197774f995
5b5cc741e4d2b4197774f995- 1K=2 & L=3false
- 2K=1 & L=4true
- 3K=1 & L=2false
- 4K=3 & L=3false
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Answer : 2. "K=1 & L=4"
Explanation :
Answer: B) K=1 & L=4 Explanation: As per divisibility rule a number is divisible by 6 means it should be divisible by 2 and 3 case 1 : the divisibility rule for 2 is the number should be end with even number in this case R =2 & R=4 case 2 : The divisibility rule for 3 is the sum of numbers should be divisible by 3so if we take option (2) Q=1 & R=4 the sum is 39 if we take option (3) Q=1 & R=2 the sum is 37 So Option (2) is correct 39 is divided by 3