IIT JEE Practice Question and Answer

Q: Find the greatest number that will divide 964, 1238 and 1400 leaving remainder of 41,31 and 51 respectively ? 1570 0

  • 1
    64
    Correct
    Wrong
  • 2
    69
    Correct
    Wrong
  • 3
    71
    Correct
    Wrong
  • 4
    58
    Correct
    Wrong
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Answer : 3. "71"
Explanation :

Answer: C) 71 Explanation: To find the greatest number which divides the numbers 964, 1238 and 1400 leaving the remainders 41, 31 and 51 is nothing but the HCF of (964 - 41), (1238 - 31), (1400 - 51). Therefore, HCF of 923, 1207 and 1349 is 71.

Q: Fill in the blanks with the appropriate words. Countries which _________ still undergoing the economic processes_________ known as developing countries. 1300 0

  • 1
    are, are
    Correct
    Wrong
  • 2
    are, is
    Correct
    Wrong
  • 3
    is, are
    Correct
    Wrong
  • 4
    were, are
    Correct
    Wrong
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Answer : 1. "are, are"
Explanation :

Answer: A) are, are Explanation:

Q: You drive to the store at 20 kmph and return by the same route at 30 kmph. Discounting the time spent at the store, what was your average speed ? 1057 0

  • 1
    25 kmph
    Correct
    Wrong
  • 2
    24 kmph
    Correct
    Wrong
  • 3
    26 kmph
    Correct
    Wrong
  • 4
    22 kmph
    Correct
    Wrong
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Answer : 2. "24 kmph"
Explanation :

Answer: B) 24 kmph Explanation: Average speed=total distance/total timeLet distance to store be  Kthen, total time =(K/20)+(K/30)=K/12and, total time =(2K)so average speed= 2K / (K/12) = 24kmph.

Q: Choose the word which gives best meaning to the sentence from the given options. His recent success ______ him more arrogant than what he used to be 2823 0

  • 1
    make
    Correct
    Wrong
  • 2
    have make
    Correct
    Wrong
  • 3
    was making
    Correct
    Wrong
  • 4
    has made
    Correct
    Wrong
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Answer : 4. "has made"
Explanation :

Answer: D) has made Explanation: HIS RECENT SUCCESS HAS MADE HIM MORE ARROGANT THAN WHAT HE USED.

Q: In a certain encryption pattern, HARD is coded as 1357 and SOFT is coded as 2468, What will 21448 stand for ? 3621 0

  • 1
    SHAFT
    Correct
    Wrong
  • 2
    SHOOT
    Correct
    Wrong
  • 3
    RAFTS
    Correct
    Wrong
  • 4
    ROOTS
    Correct
    Wrong
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Answer : 2. "SHOOT"
Explanation :

Answer: B) SHOOT Explanation: AS HARD is coded as "1357" and SOFT is coded as "2468"So H is coded as 1, A as 3, R as 5, D as 7and S as 2, O as 4, F as 6, T as 8 Now in 21448, go number by number2 is the code for S1 is the code for H4 is the code for Oand 8 is the code for T hence, 21448 will stand for SHOOT

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Answer : 1. "131 calls"
Explanation :

Answer: A) 131 calls Explanation: 1st supporter recieve 440 calls 2nd supporter recieve 360 calls 3rd supporter recieve 300 calls So total calls = 1100 calls ; Calls this month= 1500 So remaining calls to be distributed is 400 So Now Ratio 1st:2nd:3rd ==> 440:360:300=> 22:18:15 Now No. of More Calls 2nd supporter will get => [18/(22+18+15)] x 400=> (18/55) x 400 => 131 CallsSo 131 more Calls than last month.

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Answer : 1. "Only a follows"
Explanation :

Answer: A) Only a follows Explanation: The statement mentions that chances of heart ailments are greatly reduced by a regular half-hour exercise. So, a follows. However, it talks of only reducing the probability which does not mean that persons involved in sedentary jobs shall definitely suffer from heart ailments. So, b does not follow. Hence, concusion a only follows the given statement.

Q: If a number 72k23l is divisible by 88. Then find value of k and l ? 2173 0

  • 1
    k=8 & l=2
    Correct
    Wrong
  • 2
    k=7 & l=2
    Correct
    Wrong
  • 3
    k=8 & l=3
    Correct
    Wrong
  • 4
    k=7 & l=1
    Correct
    Wrong
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Answer : 2. "k=7 & l=2"
Explanation :

Answer: B) k=7 & l=2 Explanation: If a number to be divisile by 88, it should be divisible by both "8" and "11" Check for '8' :For a number to be divisible by "8", the last 3-digit should be divisible by "8"Here 72x23y --> last 3-digit is '23y'So y=2 [ (i.e) 232 is absolutely divisible by "8"] Chech for '11' :For a number to be divisible by "11" , sum of odd digits - sum of even digits should be divisible by "11"(7 + x + 3) - (2 + 2 + y)(7 + x + 3) - (2 + 2 + 2)(10 + x) - 6 should be divisible by "11"for x = 7=> 17 - 6 = 11 [ which is absolutely divisible by "11"] So x = 7 , y= 2.

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