IIT JEE Practice Question and Answer

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Answer : 4. "Rs. 1,00,000"
Explanation :

Answer: D) Rs. 1,00,000 Explanation: Deepa invested Rs.50,000 for 12 months, Rs.(50000 + 20000) for 12 months and Rs.(50000 + 20000 + 20000) for 12 months.i.e, she invested Rs.50,000 for 12 months, Rs.70000 for 12 months and Rs.90000 for 12 months.Sushma invested Rs. 70000 for 2 years; i.e, Rs.70000 for 24 monthsAnd, Avanthi invested Rs.70000 for 1 year; i.e, Rs. 70000 for 12 months. Their investing ratio:Deepa : Sushma : Avanthi = (50,000 x 12 + 70000 x 12 + 90000 x 12):(70000 x 24):(70000 x 12)= (25,20,000):(16,80,000):(8,40,000) = 252:168:84 = 3:2:1 Total profit for 3 years = Rs.3,00,000Therefore, Sushma's share = Rs.(3,00,000 x 2 /(3+2+1)) = Rs.(3,00,000 x 2/6) = Rs.1,00,000.

Q: Bill : Law :: ? : Insect 3945 0

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    Pupa
    Correct
    Wrong
  • 2
    Stage
    Correct
    Wrong
  • 3
    Larva
    Correct
    Wrong
  • 4
    Bird
    Correct
    Wrong
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Answer : 3. "Larva"
Explanation :

Answer: C) Larva Explanation: A Bill becomes a Law; a Larva becomes an insect. (Or) A Bill turns into a law; a Larva turns into an Insect.

Q: Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work  ? 3944 0

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    18 days
    Correct
    Wrong
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    20 days
    Correct
    Wrong
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    16 days
    Correct
    Wrong
  • 4
    14 days
    Correct
    Wrong
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Answer : 2. "20 days"
Explanation :

Answer: B) 20 days Explanation: (5m + 9w)10 = (6m + 12w)8  => 50m + 90w = 48w + 96 w    => 1m = 3w 5m + 9w = 5m + 3m = 8m   8 men can do the work in 10 days. 3m +3w = 3m + 1w = 4m So, 4 men can do the work in (10 x 8)/4 = 20 days.

Q: There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was : 3938 0

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    20
    Correct
    Wrong
  • 2
    35
    Correct
    Wrong
  • 3
    54
    Correct
    Wrong
  • 4
    40
    Correct
    Wrong
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Answer : 1. "20"
Explanation :

Answer: A) 20 Explanation: Numbers of students in section A = x ∴ Numbers of students in section B and C = (100 – x) ∴ x 70 + (100 – x) 87.5 = 84 100 => 70x + 87.5 100 – 87.5x = 8400 => 8750 – 17.5x = 8400 => 17.5x = 8750 – 8400 => x = 20.

Q: If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price. 3936 0

  • 1
    6:31
    Correct
    Wrong
  • 2
    11:30
    Correct
    Wrong
  • 3
    7:30
    Correct
    Wrong
  • 4
    31:6
    Correct
    Wrong
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Answer : 3. "7:30"
Explanation :

Answer: C) 7:30 Explanation: Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.M.P. = (6/5) S.P.Since the percentage discount = Percentage profit,65S.P - S.P65S.P×100 = S.P -C.PC.P×100Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.PM.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.PTherefore, Ratio of discount to C.P= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]= 7/30   Therefore, the ratio is 7 : 30

Q: Which supercomputer is developed by the Indian Scientists? 3935 0

  • 1
    Super 3
    Correct
    Wrong
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    Param 808
    Correct
    Wrong
  • 3
    Super 149
    Correct
    Wrong
  • 4
    Param 8000
    Correct
    Wrong
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Answer : 4. "Param 8000"
Explanation :

Answer: D) Param 8000 Explanation: PARAM 8000 was was the first supercomputer developed by Indian scientists launched on July 01, 1991 is considered India's first supercomputer.   It was indigenously built in 1991 by Centre for Development of Advanced Computing and was replicated and installed at ICAD Moscow in 1991 under Russian collaboration.

Q: Vinod have 20 rupees. He bought 1, 2, 5 rupee stamps. They are different in numbers by the reason of no change, the shop keeper gives 3 one rupee stamps. So how many stamps Vinod have ? 3928 0

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    10
    Correct
    Wrong
  • 2
    18
    Correct
    Wrong
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    12
    Correct
    Wrong
  • 4
    15
    Correct
    Wrong
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Answer : 1. "10"
Explanation :

Answer: A) 10 Explanation: Given total rupees = 20 RsNo. of one rupee stamps = 3Now, remaining money = Rs. 17With that he buys only 2 and 5 rupee stampsLet number of Rs. 5 stamps = KLet number of Rs. 2 stamps = L5K + 2L = 17K = 3, L = 1 (possible)L = 6, K = 1 (possible)=> But given that they are different in number so, K is not equal to 3one rupee stamps = 32 two stamps = 65 rupee stamps = 1Total number of stamps = 10.

Q: Find the missing number in the given number series? 2676, 445, ?, 21,6, 2, 1 3927 0

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    88
    Correct
    Wrong
  • 2
    92
    Correct
    Wrong
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    96
    Correct
    Wrong
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    102
    Correct
    Wrong
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Answer : 1. "88"
Explanation :

Answer: A) 88 Explanation: The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that, From right side, 1 1 x 1 + 1 = 2 2 x 2 + 2 = 6 6 x 3 + 3 = 21 21 x 4 + 4 = 88 88 x 5 + 5 = 445 445 x 6 + 6 = 2676   Hence the missing number in the given number series is 88.

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