IIT JEE Practice Question and Answer
8Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 3551 05b5cc74fe4d2b4197774fb1c
5b5cc74fe4d2b4197774fb1c- 175 minfalse
- 282 minfalse
- 390 mintrue
- 4101 minfalse
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Answer : 3. "90 min"
Explanation :
Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.
Q: A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is: 3544 05b5cc6bde4d2b4197774d8de
5b5cc6bde4d2b4197774d8de- 1A gain of Rs. 27false
- 2A loss of Rs. 37true
- 3A loss of Rs. 27false
- 4A gain of Rs. 37false
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Answer : 2. "A loss of Rs. 37"
Explanation :
Answer: B) A loss of Rs. 37 Explanation: As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order). The overall resultant will remain same. So final amount with the person will be (in all cases): = 64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27 Hence the final result is: 64 − 27 = 37 A loss of Rs.37
Q: Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ? 3536 05b5cc715e4d2b4197774f463
5b5cc715e4d2b4197774f463- 17 : 12false
- 28 : 13true
- 39 : 4false
- 42 : 5false
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Answer : 2. "8 : 13"
Explanation :
Answer: B) 8 : 13 Explanation: To get the solution that contains 1 part of milk and two parts of water,they must be mixed in the ratio as7x+6x/5y+11y = 1/226x = 16yx/y = 16/26x/y = 8/13
Q: Ezra cup is associated with which sports? 3533 05b5cc651e4d2b4197774bcd0
5b5cc651e4d2b4197774bcd0- 1Hockeyfalse
- 2Polotrue
- 3Rowingfalse
- 4Footballfalse
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Answer : 2. "Polo"
Explanation :
Answer: B) Polo Explanation: The Ezra Cup is a popular polo tournament conducted annually in India. The Calcutta Polo Club runs this oldest and first ever Polo Trophy. The first Ezra Cup was held in 1880. After a period of inactivity, it has now been revived by Mr. Keshav Bangur, Calcutta Polo Club's president.
Q: Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ? 3509 05b5cc73ae4d2b4197774f8ce
5b5cc73ae4d2b4197774f8ce- 1E = 15 & Y = 3false
- 2E = 14 & Y = 12false
- 3E = 40 & Y = 22false
- 4E = 4 & Y = 2true
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Answer : 4. "E = 4 & Y = 2"
Explanation :
Answer: D) E = 4 & Y = 2 Explanation: Let the the age of the elder boy = E Let the the age of the younger boy = Y Given that Y = cube root of EY => Y3 = EY => E = Y2 .....(1)By the condition of number replacement the age of the father is YE The Mother's age = EY/2 But she is 3 years less than father => EY/2 + 3 = YE2YE = EY + 6 ......(2) Then now from the given options we can identify which satisfies the all the conditions. Here Y =2 and E = 4 satisfies all the conditions.
Q: Find out which part of a sentence has an error and mark the answer corresponding to the appropriate letter (A, B, C). If a sentence is free from errors, mark (D) as the answer. He flew( 3490 05b5cc6d6e4d2b4197774e69d
5b5cc6d6e4d2b4197774e69d- 1/ over extensively(false
- 2C). If a sentence is free from errors, mark (D) as the answer. He flew(A) / over extensively(B)true
- 3. If a sentence is free from errors, mark (false
- 4as the answer. He flew(A) / over extensively(B) / the pacific last winter(C) / No error(D)false
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Answer : 2. "C). If a sentence is free from errors, mark (D) as the answer.
He flew(A) / over extensively(B)"
Explanation :
Answer: B) B Explanation: 'Extensively' is describing the verb 'flew' and should be placed after the verb and thus the correct phrase should be 'extensively over'. The error is in the second part of the sentence.
Q: Which of the following is not an allotrope of carbon? 3481 05b5cc683e4d2b4197774c292
5b5cc683e4d2b4197774c292- 1Diamondfalse
- 2Graphenefalse
- 3Ethylenetrue
- 4Buckminsterfullerenefalse
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Answer : 3. "Ethylene"
Explanation :
Answer: C) Ethylene Explanation: Allotropes are different structural modifications of an element, that is, each of two or more different physical forms in which an element can exist. Carbon is capable of forming many allotropes due to its valency. Well-known forms of carbon include charcoal, diamond, graphite, buckminsterfullerene and graphene. Hence, Ethylene is not an allotrope of Carbon.
Q: Excel displays the current cell address in the 3478 05b5cc655e4d2b4197774bd44
5b5cc655e4d2b4197774bd44- 1Title Barfalse
- 2Name Boxtrue
- 3Status Barfalse
- 4Formula barfalse
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Answer : 2. "Name Box"
Explanation :
Answer: B) Name Box Explanation: