IIT JEE Practice Question and Answer
8Q: Ramu rides his bike at an average speed of 45 km/hr and reaches his desitination in four hours. Somu covers the same distance in six hours. If Ramu covered his journey at an average speed which was 9 km/hr less and Somu covered his journey at an average speed which was 10 km/hr more, then the difference in their times taken to reach the destination would be (in minutes). 3909 05b5cc6e5e4d2b4197774ed15
5b5cc6e5e4d2b4197774ed15- 118 minfalse
- 230 mintrue
- 327 minfalse
- 432 minfalse
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Answer : 2. "30 min"
Explanation :
Answer: B) 30 min Explanation: Distance travelled by Ramu = 45 x 4 = 180 km Somu travelled the same distance in 6 hours. His speed = 180/6 = 30 km/hr Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr. Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively. Hence difference in the time taken = 0.5 hours = 30 minutes.
Q: Which alphabet replaces the question mark ? 63 O 4972 T 3796 L 1514 ? 58 3905 05b5cc70ee4d2b4197774f380
5b5cc70ee4d2b4197774f380- 1Afalse
- 2Bfalse
- 3Ctrue
- 4Dfalse
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Answer : 3. "C"
Explanation :
Answer: C) C Explanation: 6-3 = 3 9-4 = 5 (3x5=15) 15=O7-2 = 5 7-3 = 4 (5x4=20) 20=T9-6 = 3 5-1 = 4 (3x4=12) 12=L Similarly, 4-1 = 3 8-5 = 1 (3x1=3) 3=C
Q: A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ? 3903 05b5cc73ae4d2b4197774f8d8
5b5cc73ae4d2b4197774f8d8- 17 hrsfalse
- 27.5 hrstrue
- 38 hrsfalse
- 48.25 hrsfalse
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Answer : 2. "7.5 hrs"
Explanation :
Answer: B) 7.5 hrs Explanation: Let there are L men job requires LK man hours. job completed in first 4 hrs = L x 4 = 4L job completed in next 4 hrs = 4 x L/2 = 2L job completed in next 4 hrs = 4 x L/4 = L job completed in last 4 hrs = 4 x L/8 = L/2 4L + 2L + L + L/2 = KL K = 7+1/2 = 7.5 hours.
Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 3899 05b5cc74fe4d2b4197774fb1c
5b5cc74fe4d2b4197774fb1c- 175 minfalse
- 282 minfalse
- 390 mintrue
- 4101 minfalse
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Answer : 3. "90 min"
Explanation :
Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.
Q: Find out which part of a sentence has an error and mark the answer corresponding to the appropriate letter (A, B, C). If a sentence is free from errors, mark (D) as the answer. He flew( 3898 05b5cc6d6e4d2b4197774e69d
5b5cc6d6e4d2b4197774e69d- 1/ over extensively(false
- 2C). If a sentence is free from errors, mark (D) as the answer. He flew(A) / over extensively(B)true
- 3. If a sentence is free from errors, mark (false
- 4as the answer. He flew(A) / over extensively(B) / the pacific last winter(C) / No error(D)false
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Answer : 2. "C). If a sentence is free from errors, mark (D) as the answer.
He flew(A) / over extensively(B)"
Explanation :
Answer: B) B Explanation: 'Extensively' is describing the verb 'flew' and should be placed after the verb and thus the correct phrase should be 'extensively over'. The error is in the second part of the sentence.
Q: What is the main component of biogas and natural gas? 3884 05b5cc69ce4d2b4197774c825
5b5cc69ce4d2b4197774c825- 1Carbon dioxidefalse
- 2Butanefalse
- 3Hydrogen Sulphidefalse
- 4Methanetrue
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Answer : 4. "Methane"
Explanation :
Answer: D) Methane Explanation: Methane is the main component of biogas and natural gas.
Q: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5% ? 3868 05b5cc6e9e4d2b4197774eded
5b5cc6e9e4d2b4197774eded- 1Rs. 500true
- 2Rs. 245false
- 3Rs. 1250false
- 4Rs. 635false
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Answer : 1. "Rs. 500"
Explanation :
Answer: A) Rs. 500 Explanation: (kx5x1)/100 + [(1500 - k)x6x1]/100 = 85 5k/100 + 90 – 6k/100 = 85 k/100 = 5 => k = 500
Q: A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ? 3867 05b5cc6cde4d2b4197774e1c2
5b5cc6cde4d2b4197774e1c2- 11080 cmfalse
- 2180 mfalse
- 3108 mtrue
- 4118 cmfalse
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Answer : 3. "108 m"
Explanation :
Answer: C) 108 m Explanation: We know the rule that, At particular time for all object , ratio of height and shadow are same. Let the height of the pole be 'H' Then 188=H48 => H = 108 m.