Maths Practice Question and Answer
8Q: A cow was standing on a bridge, 5m away from the middle of the bridge. A train was coming towards the bridge from the ends nearest to the cow. Seeing this cow ran towards the the train and managed to escape when the train was 2m away from bridge. If it had run in the opposite direction, it would hit by the train 2m before the end of the bridge. What is the lenght of the bridge in meters assuming the speed of the train is 4 times that of cow ? 93392 35b5cc705e4d2b4197774f249
5b5cc705e4d2b4197774f249- 122 mtsfalse
- 228 mtsfalse
- 332 mtstrue
- 434 mtsfalse
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Answer : 3. "32 mts"
Explanation :
Answer: C) 32 mts Explanation: let 'b' be the Length of bridge from cow to the near end of the bridge and 'a' be the distance of the train from the bridge. 'x' be speed of cow => '4x' speed of trainThen the total length of the bridge 2b + 10.(a-2)/4x = b/x=> a-2 = 4b........(1)Now if it had run in opposite direction(a+2b+10-2)/4x = (b+10-2)/x=> a - 2b = 24......(2)Solving (1) and (2)b = 11 , Therefore length of the bridge is 2 x 11 + 10 = 32mts.
Q: A man went downstream for 28 km in a motor boat and immediately returned. It took the man twice as long to make the return trip. If the speed of the river flow were twice as high, the trip downstream and back would take 672 minutes. Find the speed of the boat in still water and the speed of the river flow. 52795 05b5cc672e4d2b4197774c0c8
5b5cc672e4d2b4197774c0c8- 112 km/hr, 3 km/hrfalse
- 29 km/hr, 3 km/hrtrue
- 38 km/hr, 2 km/hrfalse
- 49 km/hr, 6 km/hrfalse
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Answer : 2. "9 km/hr, 3 km/hr"
Explanation :
Answer: B) 9 km/hr, 3 km/hr Explanation: Let the speed of the boat = p kmph Let the speed of the river flow = q kmph From the given data, 2 x 28p + q = 28p - q => 56p - 56q -28p - 28q = 0 => 28p = 84q => p = 3q. Now, given that if 283q + 2q + 283q - 2q = 67260=> 285q + 28q = 67260=> q = 3 kmph=> x =3q = 9 kmph Hence, the speed of the boat = p kmph = 9 kmph and the speed of the river flow = q kmph = 3 kmph.
Q: If Suresh borrows Rs. 36000 from Mahesh at rate of interest 6% S.I, at the end of four years how much interest Suresh has to pay along with principal amount?
50537 05ee305602bf4c404464925b9
5ee305602bf4c404464925b9- 1Rs. 12560false
- 2Rs. 12960true
- 3Rs. 13500false
- 4Rs. 14500false
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Answer : 2. "Rs. 12960"
Q: A train moving at speed of 90 km/hr crosses a pole in 7 seconds. Find the length of the train.
42155 05ee3067ef72c0e153c80603f
5ee3067ef72c0e153c80603f- 1150 mfalse
- 2165 mfalse
- 3175 mtrue
- 4170 mfalse
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Answer : 3. "175 m"
Q: A clock only with only dots marking 3, 6, 9 and 12 positions has been kept upside down in front of mirror. A person reads the time in the reflection of the clock as 4.50. What is the actual time?
33808 05e6b9605c34ec57f0d146cb6
5e6b9605c34ec57f0d146cb6- 108 : 10false
- 201 : 40true
- 304 : 50false
- 410 : 20false
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Answer : 2. "01 : 40 "
Q: A jar was full with honey. A person used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar solution. The initial amount of honey in the jar was: 30870 25b5cc7d7e4d2b41977751515
5b5cc7d7e4d2b41977751515- 11.25 kgtrue
- 21 kgfalse
- 31.5 kgfalse
- 4None of thesefalse
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Answer : 1. "1.25 kg"
Explanation :
Answer: A) 1.25 kg Explanation: Let the initial amount of honey in the jar was k, then 512 = k1 - 154 or 512 = k454 => k = 512 × 625256 => k = 1250 Hence initially the honey in the jar = 1.25 kg
Q: In a class, 3/5 of the students are girls and rest are boys. If 2/9 of the girls and 1/4 of the boys are absent. What part of the total number of students are present?
22436 45d690346fb83f62138db79c7
5d690346fb83f62138db79c7- 123/30true
- 223/36false
- 318/49false
- 417/25false
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Answer : 1. "23/30"
Q: Time in a clock is 3 : 13, what time will be appear in water ?
22264 05df9edf41d67d356b4b624a1
5df9edf41d67d356b4b624a1- 13 : 17false
- 22 : 17true
- 33 : 23false
- 42 : 13false
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