Quantitative Aptitude Practice Question and Answer

Q: If (-):(+)=12:19, then a:b=___ 5150 3

  • 1
    2:3
    Correct
    Wrong
  • 2
    1:2
    Correct
    Wrong
  • 3
    3:2
    Correct
    Wrong
  • 4
    2:1
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 3. "3:2"

Q: The ratio of number of students taking admission in a organisation X and Y was 5:8. If 20% of students exceed in organisation X and 10% of students exceed in organisation Y, then new ratio of students is 5148 1

  • 1
    15:22
    Correct
    Wrong
  • 2
    15:16
    Correct
    Wrong
  • 3
    5:4
    Correct
    Wrong
  • 4
    5:7
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 1. "15:22"

Q:

The number of females in the Marketing department are approximately what percent of the total employees in marketing and customer Relation department together?

5121 0

  • 1
    26
    Correct
    Wrong
  • 2
    36
    Correct
    Wrong
  • 3
    6
    Correct
    Wrong
  • 4
    46
    Correct
    Wrong
  • 5
    16
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 5. "16"

Q: Two boys and a girl can do a work in 5 days, while a boy and 2 girls can do it in 6 days. If the boy is paid at the rate of 28$ a week, what should be the wages of the girl a week ? 5116 0

  • 1
    24 $
    Correct
    Wrong
  • 2
    22 $
    Correct
    Wrong
  • 3
    16 $
    Correct
    Wrong
  • 4
    14 $
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 3. "16 $"
Explanation :

Answer: C) 16 $ Explanation: Let the 1 day work of a boy=b and a girl=g, then2b + g = 1/5 ---(i) andb + 2g = 1/6 ---(ii)On solving (i) & (ii), b=7/90, g=2/45As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week, so a girl will be paid 28×245790 = 16 $.

Q: What was the day of the week on 17th June, 1998 ? 5108 7

  • 1
    Monday
    Correct
    Wrong
  • 2
    Tuesday
    Correct
    Wrong
  • 3
    Wednesday
    Correct
    Wrong
  • 4
    Friday
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 3. "Wednesday"
Explanation :

Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.

Q: 56% of 225 + 20% of 150 = ? - 109   Find the value of '?' in the above equation 5102 0

  • 1
    264
    Correct
    Wrong
  • 2
    220
    Correct
    Wrong
  • 3
    241
    Correct
    Wrong
  • 4
    None
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 1. "264"
Explanation :

Answer: A) 264 Explanation: Given 56% of 225 + 20% of 150 = ? - 109 we know that a% of b = b% of a Now, 225% of 56 + 20% of 150 = ? - 109 200% of 56 + 25% of 56 + 20% of 150 = ? - 109 112 + 14 + 30 = ? - 109 ? = 112 + 14 + 30 + 109 ? = 264

Q: A cycle is sold for Rs.2070 at profit of 15%, at what profit of 15%, at what price it should be sold so as to earn 25% Profit. 5084 0

  • 1
    2150
    Correct
    Wrong
  • 2
    2250
    Correct
    Wrong
  • 3
    2350
    Correct
    Wrong
  • 4
    2450
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 2. "2250"

Q: A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ? 5078 0

  • 1
    20 km
    Correct
    Wrong
  • 2
    16 km
    Correct
    Wrong
  • 3
    14 km
    Correct
    Wrong
  • 4
    10 km
    Correct
    Wrong
  • Show Answer
  • Workspace

Answer : 4. "10 km"
Explanation :

Answer: D) 10 km Explanation: Let distance = x km.Time taken at 3 kmph : dist/speed = x/3 = 20 min late.time taken at 4 kmph : x/4 = 30 min earlierdifference between time taken : 30-(-20) = 50 mins = 50/60 hours.x/3- x/4 = 50/60x/12 = 5/6x = 10 km.

  Report Error

Please Enter Message
Error Reported Successfully

  Report Error

Please Enter Message
Error Reported Successfully

  Report Error

Please Enter Message
Error Reported Successfully

  Report Error

Please Enter Message
Error Reported Successfully

  Report Error

Please Enter Message
Error Reported Successfully

  Report Error

Please Enter Message
Error Reported Successfully

  Report Error

Please Enter Message
Error Reported Successfully

  Report Error

Please Enter Message
Error Reported Successfully