Quantitative Aptitude Practice Question and Answer
8Q: What is the number of digits in 333? Given that log3 = 0.47712? 5487 05b5cc7d0e4d2b41977751209
5b5cc7d0e4d2b41977751209- 112false
- 213true
- 314false
- 415false
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Answer : 2. "13"
Explanation :
Answer: B) 13 Explanation: Let Let x=333 = 333 Then, logx = 33 log3 = 27 x 0.47712 = 12.88224 Since the characteristic in the resultant value of log x is 12 ∴The number of digits in x is (12 + 1) = 13 Hence the required number of digits in 333is 13.
Q: For x∈N, x>1, and p=logxx+1, q=logx+1x+2 then which one of the following is correct? 6902 25b5cc7d0e4d2b419777511ff
5b5cc7d0e4d2b419777511ff- 1p < qfalse
- 2p = qfalse
- 3p > qtrue
- 4can't be determinedfalse
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Answer : 3. "p > q"
Explanation :
Answer: C) p > q Explanation: kl>k+1l+1 for (k,l) > 0 and k > l Let k = x+1 and l = x Therefore, x+1x>(x+1)+1(x)+1 (x + 1) > x Therefore, log(x+1)log(x)>log(x+2)log(x+1) ⇒logxx+1 >logx+1x+2
Q: The Value of logtan10+logtan20+⋯⋯+logtan890 is 1428 15b5cc7d0e4d2b41977751204
5b5cc7d0e4d2b41977751204- 1-1false
- 20true
- 31/2false
- 41false
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Answer : 2. "0"
Explanation :
Answer: B) 0 Explanation: = log tan10+log tan890 + log tan20+ log tan880+⋯⋯+log tan450 = log [tan10 × tan890] + log [tan20 × tan880 ] +⋯⋯+log1 ∵ tan(90-θ)=cotθ and tan 450=1 = log 1 + log 1 +.....+log 1 = 0.
Q: A and B runs around a circular track. A beats B by one round or 10 minutes. In this race, they had completed 4 rounds. If the race was only of one round, find the A's time over the course: 4095 05b5cc7d0e4d2b419777511e0
5b5cc7d0e4d2b419777511e0- 18 minfalse
- 27.5 mintrue
- 312.5 minfalse
- 412 minfalse
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Answer : 2. "7.5 min"
Explanation :
Answer: B) 7.5 min Explanation: B runs around the track in 10 min. i.e , Speed of B = 10 min per round Therefore, A beats B by 1 round Time taken by A to complete 4 rounds = Time taken by B to complete 3 rounds = 30 min Therefore, A's speed = 30/4 min per round = 7.5 min per round Hence, if the race is only of one round A's time over the course = 7 min 30 sec
Q: Amit can do a piece of work in 45 days, but Bharath can do the same work in 5 days less, than Amit, when working alone. Amit and Bharath both started the work together but Bharath left after some days and Amit finished the remaining work in 56 days with half of his efficiency but he did the work with Bharath with his complete efficiency. For how many days they had worked together? 3815 05b5cc7d0e4d2b419777511db
5b5cc7d0e4d2b419777511db- 16false
- 28true
- 39false
- 412false
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Answer : 2. "8"
Explanation :
Answer: B) 8 Explanation: AmitBharatNo.of Days4540Efficiency2.22Percent(=145)2.5 Percent(=140) Amit did the work in 56 days = 56×145×2=2845 Therefore, Rest work 17/45 was done by Amit and Bharath = 174517360 = 8 days ( since Amit and Bharath do the work in one day = 145+140=17360)
Q: A can do a piece of work in 10 days, B in 15 days. They work together for 5 days, the rest of the work is finished by C in two more days. If they get Rs. 3000 as wages for the whole work, what are the daily wages of A, B and C respectively (in Rs): 1804 05b5cc7d0e4d2b419777511d6
5b5cc7d0e4d2b419777511d6- 1200, 250, 300false
- 2300, 200, 250true
- 3200, 300, 400false
- 4None of thesefalse
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Answer : 2. "300, 200, 250"
Explanation :
Answer: B) 300, 200, 250 Explanation: A's 5 days work = 50% B's 5 days work = 33.33% C's 2 days work = 16.66% [100- (50+33.33)] Ratio of contribution of work of A, B and C = 50 : 3313 : 1623 = 3 : 2 : 1 A's total share = Rs. 1500 B's total share = Rs. 1000 C's total share = Rs. 500 A's one day's earning = Rs.300 B's one day's earning = Rs.200 C's one day's earning = Rs.250
Q: Two pipes A and B can fill a tank in 24 hours and 1717 hours respectively. Harihar opened the pipes A and B to fill an empty tank and some times later he closed the taps A and B , when the tank was supposed to be full. After that it was found that the tank was emptied in 2.5 hours because an outlet pipe "C" connected to the tank was open from the beginning. If Harihar closed the pipe C instead of closing pipes A and B the remaining tank would have been filled in : 9682 05b5cc7cfe4d2b419777511cc
5b5cc7cfe4d2b419777511cc- 12 hoursfalse
- 28 hourstrue
- 36 hoursfalse
- 44 hoursfalse
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Answer : 2. "8 hours"
Explanation :
Answer: B) 8 hours Explanation: Efficiency of Inlet pipe A = 4.16% 10024 Efficiency of Inlet pipe B = 5.83% 1001717 Therefore, Efficiency of A and B together = 100 % Now, if the efficiency of outlet pipe be x% then in 10 hours the capacity of tank which will be filled = 10 * (10 - x) Now, since this amount of water is being emptied by 'C' at x% per hour, then 10x10-xx=2.5 hrs => x = 8 Therefore, in 10 hours 20% tank is filled only. Hence, the remaining 80% of the capacity will be filled by pipes A and B in 80/10 = 8 hours
Q: The ratio of earnings of A and B is 4:5. If the earnings of A increase by 20% and the earnings of B decrease by 20%, the new ratio of their earnings becomes 6:5. What are A's earnings? 1607 05b5cc7c9e4d2b41977750ed6
5b5cc7c9e4d2b41977750ed6- 1Rs.22,000false
- 2Rs.27,500false
- 3Rs. 26,400false
- 4Cannot be determinedtrue
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Answer : 4. "Cannot be determined"
Explanation :
Answer: D) Cannot be determined Explanation: