Quantitative Aptitude Practice Question and Answer
8Q: 30 Men can complete a work in 25 days. In how many days can 75 men complete it? 4637 25d1498d097a68b089a7aa7a0
5d1498d097a68b089a7aa7a0- 115false
- 212false
- 316false
- 410true
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Answer : 4. "10"
Q: A single person takes 4 minutes to type a page, if from 12 noon to 1.00 pm., 1080 pages are to be typed, how many persons should be employed on this job? 4622 05d148d649aeb0a08f1e67464
5d148d649aeb0a08f1e67464- 1108false
- 260false
- 390false
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Answer : 4. "72"
Q: Two trains namely X & Y leave station 'A' at 6.30am and 7.40am and travel at 30km/hr and 40 km/hr respectively. How many kms from 'A' will the trains meet ? 4574 05b5cc745e4d2b4197774fa5e
5b5cc745e4d2b4197774fa5e- 1140 kmstrue
- 2120 kmsfalse
- 396 kmsfalse
- 4142 kmsfalse
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Answer : 1. "140 kms"
Explanation :
Answer: A) 140 kms Explanation: It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, theDistance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 kmSo train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutesSo distance from A = Distance traveled by 2nd train in 3 hr. 30 min = 40 x 3.5 = 140 km.
Q: Find out the wrong number in the following series: 5, 15, 30, 80, 180, 540, 1080 4538 05b5cc70ee4d2b4197774f376
5b5cc70ee4d2b4197774f376- 1540false
- 2180false
- 330false
- 480true
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Answer : 4. "80"
Explanation :
Answer: D) 80 Explanation: There should be 90 instead of 80so we can have a series5, 5x3, 15x2, 30x3, 90x2, 180x3, 540x2 and 1080x3 and so on...
Q: Find the Odd One Out of the following Number Series? 3, 14, 36, 67, 113, 168 4533 05b5cc6b1e4d2b4197774d34b
5b5cc6b1e4d2b4197774d34b- 114false
- 236false
- 367true
- 4113false
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Answer : 3. "67"
Explanation :
Answer: C) 67 Explanation: Here the given number series is 3, 14, 36, 67, 113, 168 It follows a pattern that 3 3 + 1 x 11 = 3 + 11 = 14 14 + 2 x 11 = 14 + 22 = 36 36 + 3 x 11 = 36 + 33 = 69 69 + 4 x 11 = 69 + 44 = 113 113 + 5 x 11 = 113 + 55 = 168 Hence, the wrong number is 67.
Q: Find the next number in the series 141,137,146,130,155,119,... 4510 05b5cc771e4d2b4197774ffc1
5b5cc771e4d2b4197774ffc1- 1147false
- 2168true
- 3162false
- 4182false
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Answer : 2. "168"
Explanation :
Answer: B) 168 Explanation: The pattern is -4, +9,-16, +25, -36 The next number=119+49=168
Q: A son and father goes for boating in river upstream . After rowing for 1 mile son notices the hat of his father falling in the river. After 5 min he tells his father that his hat has fallen. So they turn round and are able to pick the hat at the point from where they began boating after 5min. Find the speed of river in miles/hours ? 4504 05b5cc711e4d2b4197774f3d7
5b5cc711e4d2b4197774f3d7- 14 mile/hrfalse
- 26 mile/hrtrue
- 32 mile/hrfalse
- 45 mile/hrfalse
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Answer : 2. "6 mile/hr"
Explanation :
Answer: B) 6 mile/hr Explanation: Let the speed of river and boat be 'r' m/min and 'b' m/min.so relative speed in upstream (b-r)m/min and in downstream (b+r)m/min.Now in upstream distnce covered in 5 min is 5(b-r)milesso total distnce covered => 1 + 5(b-r)miles in upstreamIn downstream distance covered in 5min is 5(b+r)miles Now 1 + 5(b-r) = 5(b+r)1+5b-5r = 5b+5r1 = 10rr = 1/10 mile/min => 6 mile/hr.
Q: When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died ? 4454 05b5cc745e4d2b4197774fa18
5b5cc745e4d2b4197774fa18- 150 yrsfalse
- 260 yrstrue
- 370 yrsfalse
- 465 yrsfalse
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Answer : 2. "60 yrs"
Explanation :
Answer: B) 60 yrs Explanation: Let the Father be x years when he died Average Age 10 years ago be A Total Age 10 years ago = 6*A Total Age after 10 years(Just before father's Death) = 6A + 6*10 = 6A + 60 Father Died and Baby was born => the Total number of people in the family is Same (6) Baby born today so age of baby = 0 (6A +60 - x)/6 = 6A/6 => A + 10 -(x/6) = A => x/6 = 10 => x = 60 Therefore we can conclude that the father was 60 years old when he died.