Quantitative Aptitude Practice Question and Answer
8Q: If 25a + 25b = 115, then what is the average of a and b? 1691 05b5cc7c7e4d2b41977750daf
5b5cc7c7e4d2b41977750daf- 14.6false
- 23.4false
- 32.5false
- 4None of thesetrue
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Answer : 4. "None of these"
Explanation :
Answer: D) None of these Explanation:
Q: Excluding the stoppages, the speed of a bus is 64 km/hr and including the stoppages the speed o the bus is 48km/hr. For how many minutes does the bus stop per hour? 1392 05b5cc7c7e4d2b41977750daa
5b5cc7c7e4d2b41977750daa- 112.5 minutesfalse
- 215 minutestrue
- 310 minutesfalse
- 418 minutesfalse
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Answer : 2. "15 minutes"
Explanation :
Answer: B) 15 minutes Explanation:
Q: The Simple interest accrued on an amount of Rs. 2,500 at the end of six years is Rs.1875. What would be the simple interest accrued on an amount of Rs. 6875 at the same rate and Same period? 1672 05b5cc7c7e4d2b41977750d78
5b5cc7c7e4d2b41977750d78- 1Rs. 4,556.5false
- 2Rs. 5,025.25false
- 3Rs.5,245.5false
- 4None of thesetrue
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Answer : 4. "None of these"
Explanation :
Answer: D) None of these Explanation:
Q: A Shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net Profit or loss that he makes? 6116 05b5cc7bbe4d2b419777509d7
5b5cc7bbe4d2b419777509d7- 14%true
- 25%false
- 36%false
- 48%false
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Answer : 1. "4%"
Explanation :
Answer: A) 4% Explanation: SP of first article = Rs.1000 Profit = 20% CP = SP x 100100+P% = Rs. 25003 SP of Second Article = Rs.1000 Loss = 20% CP = SP x 100100-L% = Rs. 1250 So, Total SP = Rs.2000; Total CP = Rs.6250/3 As the CP is more than SP, he makes a loss. Loss = CP - SP = (6250/3) - 2000 = Rs.(250/3) So, Loss Percent = Lossx100/CP = 4%
Q: A and B invests Rs.10000 each, A investing for 8 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.25000, find their shares? 3201 05b5cc7bbe4d2b419777509cd
5b5cc7bbe4d2b419777509cd- 110000 and 15000true
- 215000 and 10000false
- 35000 and 20000false
- 420000 and 5000false
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Answer : 1. "10000 and 15000"
Explanation :
Answer: A) 10000 and 15000 Explanation: As both A and B invest the same amounts, the ratio of their profits at the end of the year is equal to the ratio of the time periods for which they have invested. Thus, the required ratio of their profits = A : B = 8 : 12 = 2 : 3. Hence, share of A in the total profit = 2 x 25000/5 = Rs.10000 Similarly, share of B in the total profit = 3 x 25000/5 = Rs.15000
Q: By selling an article at Rs.800, a shopkeeper makes a profit of 25%.At what price should he sell the article so as to make a loss of 25%? 3880 05b5cc7bbe4d2b419777509d2
5b5cc7bbe4d2b419777509d2- 1Rs.720false
- 2Rs.640false
- 3Rs.540false
- 4Rs.480true
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Answer : 4. "Rs.480"
Explanation :
Answer: D) Rs.480 Explanation: SP = Rs.800 ; Profit = 25% CP = SP x 100100+P% = 800 x 100100+25 = 640 Now, CP = Rs.640 Loss = 25% = 25% of Rs.640 = Rs.160 Thus, SP = CP - Loss = Rs.640 - Rs.160 = Rs.480
Q: If 12 men can reap 120 acres of land in 36 days, how many acres of land can 54 men reap in 54 days? 3371 05b5cc7bbe4d2b419777509be
5b5cc7bbe4d2b419777509be- 1710 acresfalse
- 2760 acresfalse
- 3810 acrestrue
- 4860 acresfalse
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Answer : 3. "810 acres"
Explanation :
Answer: C) 810 acres Explanation: 12 men120 acres36 days54 men?54 days As 12 men can reap 120 acres, 54 men will be able to reap more acres in 36 days, 120 acres of land was reaped, so in 54 days, more land will be reaped. Thus, the numbers of acres that can be reaped by 54 men in 54 days = 5412x120x5436 = 810 acres
Q: In a plane 8 points are colliner out of 12 points, then the number of triangles we get with those 12 points is 955 05b5cc7b4e4d2b419777508ab
5b5cc7b4e4d2b419777508ab- 120false
- 2160false
- 3164true
- 4220false
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Answer : 3. "164"
Explanation :
Answer: C) 164 Explanation: For a triangle, we need 3 non-collinear points. So with 12 points (when all the 12 are such that any three non-collinear is12C3. But among them 8 points are collinear. If all these 8 points are different we get 8C3 triangles as they are collinear. In 12C3 triangles, we do not get 8C3 triangles Therefore, The number of triangles we get = 12C3-8C3 = 164