Quantitative Aptitude Practice Question and Answer
8Q: Find the next number in the given number series? 96, 95, 87, 78, ? 2220 05b5cc60ae4d2b4197774b5c9
5b5cc60ae4d2b4197774b5c9- 164false
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Answer : 4. "14"
Explanation :
Answer: D) 14 Explanation: The given number series is 96, 95, 87, 78, ? It follows a pattern that, 9696 - 12 = 9595 - 23 = 95 - 8 = 8787 - 32 = 87 - 9 = 7878 - 43 = 78 - 64 = 14 Hence, the next number in the given number series is 14.
Q: 82.5% of 2360? 2032 05b5cc60ae4d2b4197774b5a1
5b5cc60ae4d2b4197774b5a1- 11960false
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Answer : 3. "1947"
Explanation :
Answer: C) 1947 Explanation: Given 82.5% of 2360 82.5100 x 2360 = 0.825 x 2360 = 1947
Q: Simplify the following equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? 2507 05b5cc604e4d2b4197774b4fd
5b5cc604e4d2b4197774b4fd- 1226.65true
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Answer : 1. "226.65"
Explanation :
Answer: A) 226.65 Explanation: 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? 55.55 155.00 15.55 0.5 0.05 _______ 226.65 _______ Hence, the value of the given equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = 226.65.
Q: The ratio of two positive numbers is 3 : 5 and the average of the number is 48. What is the product of numbers? 2757 15b5cc607e4d2b4197774b558
5b5cc607e4d2b4197774b558- 13365false
- 22160true
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Answer : 2. "2160"
Explanation :
Answer: B) 2160 Explanation: Let the number be 3p and 5p ATQ, 8p = 2 x 48 p = 96/8 p = 12 The numbers are 36 and 60. Hence, the product of the numbers = 36 x 60 = 2160.
Q: Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? 1854 05b5cc60ae4d2b4197774b5b5
5b5cc60ae4d2b4197774b5b5- 15 kmphtrue
- 26 kmphfalse
- 37.5 kmphfalse
- 48 kmphfalse
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Answer : 1. "5 kmph"
Explanation :
Answer: A) 5 kmph Explanation: Let p be the speed of man in kmph According to the given data in the question, Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction => 20 x 10/60 = 8/60 (20 + p) => 200 = 160 + 8p => p = 40/8 = 5 kmph.
Q: In a class 60% of the students pass in English and 45% pass in Hindi. If 25% of them pass in both subjects, what percentage of the students fail in both the subjects? 2632 15b5cc601e4d2b4197774b440
5b5cc601e4d2b4197774b440- 120%true
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Answer : 1. "20%"
Explanation :
Answer: A) 20% Explanation: Percentage of students passed in English = 60% Percentage of students passed in Hindi = 45% Percentage of students passed in both subjects = 25% ATQ, Percentage of students passed in only English = 60 - 25 = 35% Percentage of students passed in only Hindi = 45 - 25 = 20% Therefore, Percentage of students failed = 100 - (35 + 25 + 20) = 100 - 80 = 20%.
Q: Find the wrong number in the given number series? 10, 21, 54, 109, 189 8887 05b5cc607e4d2b4197774b553
5b5cc607e4d2b4197774b553- 1189true
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Answer : 1. "189"
Explanation :
Answer: A) 189 Explanation: The given number series is 10, 21, 54, 109, 189 The series follows a pattern that 10 + 11 = 21 21 + 33 = 54 54 + 55 = 109 109 + 77 = 186 Hence the wrong number in the given number series is 189.
Q: 5 boys and 3 girls can together cultivate a 23 acre field in 4 days and 3 boys and 2 girls together can cultivate a 7 acre field in 2 days. How many girls will be needed together with 7 boys, if they cultivate 45 acres of field in 6 days? 1456 05b5cc60ae4d2b4197774b5bf
5b5cc60ae4d2b4197774b5bf- 14false
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Answer : 3. "2"
Explanation :
Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a) 2(3b + 2g) = 7 6b + 4g = 7 ........(b) Solving (a) & (b), we get b = 1, g = 1/4 Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2. Hence, number of girls required = 2