Quantitative Aptitude Practice Question and Answer
8Q: Ajay who is a King, at his eleventh hour, called his three queens and distributed his gold in the following way: He gave 50% of his wealth to his first wife, 50% of the rest to his second wife and again 50% of the rest to his third wife. If their combined share is worth1,30,900 kilograms of gold, find the quantity of gold King Ajay was having initially? 3125 05b5cc6a6e4d2b4197774cd8c
5b5cc6a6e4d2b4197774cd8c- 1153145 kgsfalse
- 2147890 kgsfalse
- 3152400 kgsfalse
- 4149600 kgstrue
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Answer : 4. "149600 kgs"
Explanation :
Answer: D) 149600 kgs Explanation: Let the total quantity of gold be p kgs. According to the question, 50% of p + 25% of p + 12.5% of p = 130900 87.5% of p = 130900 p = 130900 x 100/87.5 = 149600 kgs. Therefore, the initial gold quantity that king has = p = 149600 kgs.
Q: Find the number of factors of 9321 ? 3117 05b5cc736e4d2b4197774f832
5b5cc736e4d2b4197774f832- 14false
- 25false
- 37false
- 48true
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Answer : 4. "8"
Explanation :
Answer: D) 8 Explanation: 9321 = 3 x 13 x 239 = 31 x 13 1 x 239 1 ; add one to all the powers ie., (1+1) x (1+1) x (1+1)= 8 ; we get eight factors.
Q: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17th innings ? 3113 05b5cc6e9e4d2b4197774ee01
5b5cc6e9e4d2b4197774ee01- 134false
- 236false
- 335false
- 437true
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Answer : 4. "37"
Explanation :
Answer: D) 37 Explanation: 16x + 85 = 17(x + 3) x = 34 + 3 = 37
Q: If HCF of two numbers is 8,which of the following can never be their LCM? 3099 05b5cc75ce4d2b4197774fc5c
5b5cc75ce4d2b4197774fc5c- 132false
- 248false
- 360true
- 4152false
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Answer : 3. "60"
Explanation :
Answer: C) 60 Explanation: 60 is not a multiple of 8
Q: A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ? 3075 05b5cc731e4d2b4197774f7b5
5b5cc731e4d2b4197774f7b5- 11:3false
- 22:1false
- 33:2true
- 42:3false
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Answer : 3. "3:2"
Explanation :
Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.
Q: A thief steals half the total number of loaves of bread plus 1/2 loaf from a bakery. A second thief steals half the remaining number of loaves plus 1/2 loaf and so on. After the 5th thief has stolen there are no more loaves left in the bakery. What was the total number of loaves did the bakery have at the beginning ? 3065 05b5cc70ee4d2b4197774f33c
5b5cc70ee4d2b4197774f33c- 121false
- 211false
- 317false
- 431true
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Answer : 4. "31"
Explanation :
Answer: D) 31 Explanation: Let y be the total number of loavesa be the remaining loaves after 1st thiefb be the remaining loaves after 2nd thiefand c, d..so on after 3 and 4 the = 0 be the remaining loaves after 5th thief a = y - (y/2 + 1/2)= y/2 - 1/2 b = a - (a/2 + 1/2)= a/2 - 1/2 c = b - (b/2 + 1/2)= b/2 - 1/2 d = c - (c/2 + 1/2)= c/2 - 1/2 e = d - (d/2 + 1/2)= d/2 - 1/2we know that, e = 0,thus by substitution, we getd = 1c = 3b = 7a = 15y = 31Therefore total number of bread loaves in bakery was 31.
Q: What approximate value should come in place of the question mark(?) in the following question.
635×455÷403=?
3061 05d4aaf0011160f205237394e
5d4aaf0011160f205237394e635×455÷403=?
- 1735false
- 2795false
- 3695false
- 4685false
- 5715true
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Answer : 5. "715"
Q: Find the next number in the sequence? 28, 16, 28, 76, 274 3058 05b5cc696e4d2b4197774c59f
5b5cc696e4d2b4197774c59f- 11233false
- 21243true
- 31256false
- 41276false
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Answer : 2. "1243"
Explanation :
Answer: B) 1243 Explanation: Given number sequence is 28, 16, 28, 76, 274 Here the sequence follows a pattern that 28 28 x 0.5 + 2 = 14 + 2 = 16 16 x 1.5 + 4 = 24 + 4 = 28 28 x 2.5 + 6 = 70 + 6 = 76 76 x 3.5 + 8 = 266 + 8 = 274 274 x 4.5 + 10 = 1233 + 10 = 1243 Hence, the next number in the given number sequence is 1243.