Quantitative Aptitude Practice Question and Answer
8Q: If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ? 1511 05b5cc764e4d2b4197774fd80
5b5cc764e4d2b4197774fd80- 1100 mtsfalse
- 296 mtsfalse
- 398 mtstrue
- 4120 mtsfalse
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Answer : 3. "98 mts"
Explanation :
Answer: C) 98 mts Explanation: Let the distance between home and school is 'x'.Let actual time to reach be 't'.Thus, x/4 = t + 4 ---- (1)and x/6 = t - 30 -----(2)Solving equation (1) and (2)=> x = 98 mts.
Q: Two trains running in opposite directions cross a pole placed on the platform in 47 seconds and 31 seconds respectively. If they cross each other in 33 seconds, what is the ratio of their speeds? 843 05b5cc764e4d2b4197774fd85
5b5cc764e4d2b4197774fd85- 11:7true
- 27:1false
- 32:3false
- 43:2false
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Answer : 1. "1:7"
Explanation :
Answer: A) 1:7 Explanation: Let the speed of the trains be x and y respectively length of train1 = 47xlength of train2 = 31yRelative speed= x + yTime taken to cross each other = 33 s=> 47x+31yx+y= 33=> (47x + 31 y) = 33(x + y)=> 14x = 2y=> x/y = 2/14 = 1/7 = 1:7
Q: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ? 1129 05b5cc764e4d2b4197774fd7b
5b5cc764e4d2b4197774fd7b- 12/3false
- 21/2true
- 37/8false
- 44/5false
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Answer : 2. "1/2"
Explanation :
Answer: B) 1/2 Explanation: Multiples of 3 below 20 are 3, 6, 9, 12, 15, 18 Multiples of 5 below 20 are 5, 10, 15, 20 Required number of possibilities = 10Total number of possibilities = 20Required probability = 10/20 = 1/2.
Q: Three unbiased coins are tossed. What is the probability of getting at most two heads ? 1259 05b5cc764e4d2b4197774fd76
5b5cc764e4d2b4197774fd76- 14/3false
- 22/3false
- 33/2false
- 43/4true
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Answer : 4. "3/4"
Explanation :
Answer: D) 3/4 Explanation: Let S be the sample space.Here n(S)= 23 = 8Let E be the event of getting atmost two heads. Then,n(E) = {(H,T,T), (T,H,T), (T,T,H), (H,H,T), (T,H,H), (H,T,H)}Required probability = n(E)/n(S) = 6/8 = 3/4.
Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 2334 15b5cc761e4d2b4197774fd67
5b5cc761e4d2b4197774fd67- 11false
- 22true
- 34false
- 48false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given a2 + b2 = c2 Now 1logc+ab + 1logc-ab = logbc+a + logbc-a = logbc2-a2 = 2logbb = 2
Q: If log72 = m, then log4928 is equal to ? 1972 05b5cc761e4d2b4197774fd5d
5b5cc761e4d2b4197774fd5d- 11/(1+2m)false
- 2(1+2m)/2true
- 32m/(2m+1)false
- 4(2m+1)/2mfalse
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Answer : 2. "(1+2m)/2"
Explanation :
Answer: B) (1+2m)/2 Explanation: log4928 = 12log77×4 = 12+122log72= 12+log72= 12 + m= 1+2m2.
Q: If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x+y is equal to ? 966 05b5cc761e4d2b4197774fd62
5b5cc761e4d2b4197774fd62- 15false
- 24false
- 33false
- 42true
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Answer : 4. "2"
Explanation :
Answer: D) 2 Explanation: Since 653xy is divisible by 5 as well as 2, so y = 0.Now, 653x0 must be divisible by 8.So, 3x0 must be divisible by 8. This happens when x = 2x + y = (2 + 0) = 2.
Q: If x is a whole number, then x²(x² - 1) is always divisible by ? 1663 05b5cc761e4d2b4197774fd58
5b5cc761e4d2b4197774fd58- 14false
- 28false
- 312true
- 4Nonefalse
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Answer : 3. "12"
Explanation :
Answer: C) 12 Explanation: we can do this by trial and error method. Putting x = 2,we get 2²(2² - 1) = 12.checking with other integers, the above equation always gives a value which is a multiple of 12,So, x²(x² - 1) is always divisible by 12.