Quantitative Aptitude Practice Question and Answer

Q: 8 couples (husband and wife) attend a dance show "Nach Baliye' in a popular TV channel ; A lucky draw in which 4 persons picked up for a prize is held, then the probability that there is atleast one couple will be selected is : 3200 0

  • 1
    8/39
    Correct
    Wrong
  • 2
    15/39
    Correct
    Wrong
  • 3
    12/13
    Correct
    Wrong
  • 4
    None of these
    Correct
    Wrong
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Answer : 2. "15/39"
Explanation :

Answer: B) 15/39 Explanation: P( selecting atleast one couple) = 1 - P(selecting none of the couples for the prize)     = 1-16C1× 14C1×12C1×10C116C4=1539

Q: Find the odd one out of the following options. 3198 0

  • 1
    Sapphire
    Correct
    Wrong
  • 2
    Ruby
    Correct
    Wrong
  • 3
    Topaz
    Correct
    Wrong
  • 4
    Granite
    Correct
    Wrong
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Answer : 4. "Granite"
Explanation :

Answer: D) Granite Explanation: Except Granite all other options belong to the group of precious stones.

Q: A watch gains 5 seconds in 3 minutes and was set right at 8 AM. What time will it show at 10 PM on the same day ? 3197 0

  • 1
    10 : 27 : 41 AM
    Correct
    Wrong
  • 2
    8 : 51 : 04 AM
    Correct
    Wrong
  • 3
    9 : 45 : 15 PM
    Correct
    Wrong
  • 4
    10 : 23 : 20 PM
    Correct
    Wrong
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Answer : 4. "10 : 23 : 20 PM"
Explanation :

Answer: D) 10 : 23 : 20 PM Explanation: The watch gains 5 seconds in 3 minutes = 100 seconds in 1 hour. From 8 AM to 10 PM on the same day, time passed is 14 hours. In 14 hours, the watch would have gained 1400 seconds or 23 minutes 20 seconds. So, when the correct time is 10 PM, the watch would show 10 : 23 : 20 PM

Q: A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ? 3192 0

  • 1
    1:3
    Correct
    Wrong
  • 2
    2:1
    Correct
    Wrong
  • 3
    3:2
    Correct
    Wrong
  • 4
    2:3
    Correct
    Wrong
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Answer : 3. "3:2"
Explanation :

Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.

Q: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8,748, its purchase price was ? 3167 0

  • 1
    Rs.14,000
    Correct
    Wrong
  • 2
    Rs.12,000
    Correct
    Wrong
  • 3
    Rs. 12,800
    Correct
    Wrong
  • 4
    Rs. 15,000
    Correct
    Wrong
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Answer : 2. "Rs.12,000"
Explanation :

Answer: B) Rs.12,000 Explanation: We have P = 8748, R = -10 and n = 3Therefore, the purchase price of the machine= P1+R100n= 87481-101003= 8748 x (100/90) x (100/90) x (100/90)= 12,000.   Therefore, the purchase price of the machine was Rs. 12,000.

Q: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3157 0

  • 1
    127.5 m
    Correct
    Wrong
  • 2
    254 m
    Correct
    Wrong
  • 3
    184 m
    Correct
    Wrong
  • 4
    212 m
    Correct
    Wrong
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Answer : 1. "127.5 m"
Explanation :

Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.

Q: What is the next number in the given Number Series? 5, 24, 94, 279, ? 3153 0

  • 1
    587
    Correct
    Wrong
  • 2
    554
    Correct
    Wrong
  • 3
    489
    Correct
    Wrong
  • 4
    499
    Correct
    Wrong
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Answer : 2. "554"
Explanation :

Answer: B) 554 Explanation: The given number series follows a pattern that 5 x 5 – 1 = 24 24 x 4 – 2 = 94 94 x 3 – 3 = 279 279 x 2 – 4 = 554

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Answer : 2. "2 x (18!)"
Explanation :

Answer: B) 2 x (18!) Explanation: A person can be chosen out of 18 people in 18 ways to be seated between Musharraf and Manmohan. Now consider Musharraf, Manmohan, and the third person, sitting between them, as a single personality, we can arrange them in 17! ways but Musharraf and Manmohan can also be arranged in 2 ways.    Required number of permutations = 18 x (17!) x 2 = 2 x 18!

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