Answer: C) (p + 4) times Explanation: Let the two no's be a and b;Given product of the no's is p = ab;If the each nos is increased by 2 then the new product will be (a+2)(b+2) = ab + 2a + 2b + 4= ab + 2(a+b) + 4= p + 2(a+b) + 4Hence the new product is (p+4) times greater than twice the sum of the two original numbers.

Answer: C) 16 $ Explanation: Let the 1 day work of a boy=b and a girl=g, then2b + g = 1/5 ---(i) andb + 2g = 1/6 ---(ii)On solving (i) & (ii), b=7/90, g=2/45As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week, so a girl will be paid 28×245790 = 16 $.

Answer: D) Rs. 616 Explanation: Let the average expenditure per head be Rs. pNow, the expenditure of the mess for old students is Rs. 44pAfter joining of 15 more students, the average expenditure per head is decreased by Rs. 3 => p-3Here, given the expenditure of the mess for (44+15 = 59) students is increased by Rs. 33Therefore, 59(p-3) = 44p + 3359p - 177 = 44p + 3315p = 210 => p = 14Thus, the expenditure of the mess for old students is Rs. 44p = 44 x 14 = Rs. 616.

Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14

Answer: A) Rs. 64 Explanation: Given Loss = Rs. 40.4We know loss = cost price - selling price 40.4 = CP - 35(15)=> CP = 40.4 + 525=> CP = Rs. 565.4Now the New selling price of waffer is Rs. 18=> SP = 35(18) = 630Now Gain = SP - CP = 630 -565.4 = Rs. 64.6.

Answer: D) 253 Explanation: The first person shakes hands with 22 different people, the second person also shakes hands with 22 different people, but one of those handshakes was counted in the 22 for the first person, so the second person actually shakes hands with 21 new people. The third person, 20 people, and so on... So, 22 + 21 + 20 + 19 + 18 + 17 + 16 + 15 + 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1= n(n+1)/2 = 22 x 23 /2 = 11 x 23 = 253.

Answer: C) 1/221 Explanation: Total Combination of getting a card from 52 cards = C152 Because there is no replacement, so number of cards after getting first card= 51 Now, Combination of getting an another card= C151 Total combination of getting 2 cards from 52 cards without replacement= (C152×C151)  There are total 4 Ace in stack. Combination of getting 1 Ace is = C14   Because there is no replacement, So number of cards after getting first Ace = 3 Combination of getting an another Ace = C13 Total Combination of getting 2 Ace without replacement=C14×C13 Now,Probability of getting 2 cards which are Ace =C14×C13C152×C151 = 1/221.

Answer: C) 16/25 Explanation: If there are total 100 candidates, 40 candidates are really capable and 60 candidates are incapable.Of the candidates who are really capable = 80% 40*(80/100)=32 pass the test andof the incapable= 30%60*(30/100)=18 pass the test.Total candidates who passed the test = 32+18 = 50The proportion of the really capable students who can pass the test to the total students who can pass = 32/50 = 16/25.