Quantitative Aptitude Practice Question and Answer
8Q: The average age of seven persons sitting in a row facing east is 26 years. If the average age of the first three persons is 19 years and the average age of the last three persons is 32 years, then find the age of the person sitting in the middle of the row ? 2685 05b5cc6dce4d2b4197774e97e
5b5cc6dce4d2b4197774e97e- 132 yrsfalse
- 229 yrstrue
- 324 yrsfalse
- 427 yrsfalse
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Answer : 2. "29 yrs"
Explanation :
Answer: B) 29 yrs Explanation: Total age seven persons = (26 x 7)yearsTotal age of the first three persons and the last three persons are (19 x 3) years and (32 x 3) years respectively.Age of the person sitting in the middle of the row = 26 x 7 - 19 x 3 - 32 x 3 = 182 - 57 - 96 = 29 years.
Q: A merchant buys two items for Rs. 7500. One item he sells at a profit of 16% and the other item at 14% loss. In the deal, the merchant makes neither any profit nor any loss. What is the difference between the selling price of both the items? 2675 05b5cc69de4d2b4197774c88d
5b5cc69de4d2b4197774c88d- 1Rs. 620true
- 2Rs. 654false
- 3Rs. 725false
- 4Rs. 747false
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Answer : 1. "Rs. 620"
Explanation :
Answer: A) Rs. 620 Explanation: Let the C.P of one item is Rs. P and that of other is Rs. (7500 - P) According to the data given C.P = S.P => Px(116/100) + (7500-P)x(86/100) = 7500 => 30P = 105000 => P = 3500 Required difference between selling prices = Rs. [(3500/100) x 116] - [(4000/100) x 86] = 4060-3440 = Rs. 620
Q: A, B and C can complete a work in 10, 15 and 20 days respectively. A and B start it together. B is replaced by C after 2 days. A leave it after one more day. In how many days work was completed? 2666 05d1485969aeb0a08f1e67225
5d1485969aeb0a08f1e67225- 113false
- 2
- 3false
- 418false
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Answer : 2. " "
Q: Simplify the following equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? 2656 05b5cc604e4d2b4197774b4fd
5b5cc604e4d2b4197774b4fd- 1226.65true
- 2196.55false
- 3202.35false
- 4216.66false
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Answer : 1. "226.65"
Explanation :
Answer: A) 226.65 Explanation: 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? 55.55 155.00 15.55 0.5 0.05 _______ 226.65 _______ Hence, the value of the given equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = 226.65.
Q: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ? 2649 05b5cc6cae4d2b4197774dffc
5b5cc6cae4d2b4197774dffc- 1100true
- 21false
- 34false
- 40false
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Answer : 1. "100"
Explanation :
Answer: A) 100 Explanation: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 It is in the form of a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c Here a = 37, b = 35 & c = 28 => a + b + c = 37 + 35 + 28 = 100 Therefore, = 100
Q: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 2649 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
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Answer : 4. "9:1"
Explanation :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. The ratio of milk and water in the new mixture = 16:4 = 4:1 If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. Amount of water removed = 2 liters. Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. Now 10 lts milk is added => total milk = 18 lts The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Q: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ? 2645 05b5cc6e7e4d2b4197774edb0
5b5cc6e7e4d2b4197774edb0- 11900true
- 22100false
- 31700false
- 42000false
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Answer : 1. "1900"
Explanation :
Answer: A) 1900 Explanation: Given 2000 ---- 54 days The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days. i.e, 2000 ----- 39 days == m ---- 20 days => m x 20 = 2000 x 39 m = 3900 So total men for 20 days is 3900 => 2000 old and 1900 new reinforcement. Hence, reinforcement = 1900.
Q: What is the probability of an impossible event? 2643 05b5cc69ee4d2b4197774c995
5b5cc69ee4d2b4197774c995- 10true
- 2-1false
- 30.1false
- 41false
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Answer : 1. "0"
Explanation :
Answer: A) 0 Explanation: The probability of an impossible event is 0. The event is known ahead of time to be not possible, therefore by definition in mathematics, the probability is defined to be 0 which means it can never happen. The probability of a certain event is 1.