Quantitative Aptitude Practice Question and Answer
8Q: Simplify the following equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? 2652 05b5cc604e4d2b4197774b4fd
5b5cc604e4d2b4197774b4fd- 1226.65true
- 2196.55false
- 3202.35false
- 4216.66false
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Answer : 1. "226.65"
Explanation :
Answer: A) 226.65 Explanation: 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? 55.55 155.00 15.55 0.5 0.05 _______ 226.65 _______ Hence, the value of the given equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = 226.65.
Q: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 2647 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
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Answer : 4. "9:1"
Explanation :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. The ratio of milk and water in the new mixture = 16:4 = 4:1 If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. Amount of water removed = 2 liters. Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. Now 10 lts milk is added => total milk = 18 lts The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Q: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ? 2647 05b5cc6cae4d2b4197774dffc
5b5cc6cae4d2b4197774dffc- 1100true
- 21false
- 34false
- 40false
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Answer : 1. "100"
Explanation :
Answer: A) 100 Explanation: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 It is in the form of a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c Here a = 37, b = 35 & c = 28 => a + b + c = 37 + 35 + 28 = 100 Therefore, = 100
Q: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ? 2644 05b5cc6e7e4d2b4197774edb0
5b5cc6e7e4d2b4197774edb0- 11900true
- 22100false
- 31700false
- 42000false
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Answer : 1. "1900"
Explanation :
Answer: A) 1900 Explanation: Given 2000 ---- 54 days The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days. i.e, 2000 ----- 39 days == m ---- 20 days => m x 20 = 2000 x 39 m = 3900 So total men for 20 days is 3900 => 2000 old and 1900 new reinforcement. Hence, reinforcement = 1900.
Q: fifteen persons are sitting around a circular table facing the centre. What is the probability that three particular persons sit together ? 2643 05b5cc731e4d2b4197774f7dd
5b5cc731e4d2b4197774f7dd- 13/91true
- 22/73false
- 31/91false
- 43/73false
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Answer : 1. "3/91"
Explanation :
Answer: A) 3/91 Explanation: In a circle of n different persons, the total number of arrangements possible = (n - 1)!Total number of arrangements = n(S) = (15 – 1)! = 14 !Taking three persons as a unit, total persons = 13 (in 4 units)Therefore no. of ways for these 13 persons to around the circular table = (13 - 1)! = 12!In any given unit, 3 particular person can sit in 3!. Hence total number of ways that any three person can sit =n(E) = 12! X 3!Therefore P (E) = probability of three persons sitting together = n(E) / n(S) = 12! X 3 ! / 14!= 12!x3x2 / 14x13x12! = 6/14x13 = 3/91
Q: What is the probability of an impossible event? 2639 05b5cc69ee4d2b4197774c995
5b5cc69ee4d2b4197774c995- 10true
- 2-1false
- 30.1false
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Answer : 1. "0"
Explanation :
Answer: A) 0 Explanation: The probability of an impossible event is 0. The event is known ahead of time to be not possible, therefore by definition in mathematics, the probability is defined to be 0 which means it can never happen. The probability of a certain event is 1.
Q: 26 men can complete a piece of work in 17 days. How many more men must be hired to complete the work in 13 days? 2632 15d14995a489f2f135e08df26
5d14995a489f2f135e08df26- 19false
- 28true
- 36false
- 418false
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Answer : 2. "8"
Q: If a person having Rs. 2000 and he want to distribute this to his five children in the manner that each son having Rs. 30 more than the younger one , what will be the share of youngest child ? 2624 15b5cc74ae4d2b4197774fabd
5b5cc74ae4d2b4197774fabd- 1Rs. 175false
- 2Rs. 325false
- 3Rs. 340true
- 4Rs. 260false
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Answer : 3. "Rs. 340"
Explanation :
Answer: C) Rs. 340 Explanation: Assume first child (the youngest) get = Rs. x According to the question ;each son having Rs. 30 more than the younger one Second child will get = Rs. x + 30 Third child will get = Rs. x + 30 + 30 = x + 60 Forth child will get = Rs. x + 30 + 30 + 30 = x + 90 Fifth child will get = Rs. x + 30 + 30 + 30 + 30 = x + 120 Total amount they got = Rs. 2000 x + (x+30) + (x+60) + (x+90) + (x+120) = 20005x + 300 = 20005x = 1700x = Rs. 340So the youngest child will get Rs. 340.