Quantitative Aptitude Practice Question and Answer

Q: The percentage discount offered for "Buy 6 get 1 free is" ? 2558 0

  • 1
    85.78 %
    Correct
    Wrong
  • 2
    58. 48 %
    Correct
    Wrong
  • 3
    19.25 %
    Correct
    Wrong
  • 4
    14.285 %
    Correct
    Wrong
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Answer : 4. "14.285 %"
Explanation :

Answer: D) 14.285 % Explanation: Total Items = 7Discounted = 1Percentage = 1/7 x 100= 14.285%

Q: An alloy contains gold and silver in the ratio 5 : 8 and another alloy contains gold and silver in the ratio 5 : 3. If equal amount of both the alloys are melted together, then the ratio of gold and silver in the resulting alloy is ? 2553 0

  • 1
    113/108
    Correct
    Wrong
  • 2
    105/103
    Correct
    Wrong
  • 3
    108/115
    Correct
    Wrong
  • 4
    103/113
    Correct
    Wrong
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Answer : 2. "105/103"
Explanation :

Answer: B) 105/103 Explanation: As given equal amounts of alloys are melted, let it be 1 kg. Required ratio of gold and silver = 513 + 58813 + 38 = 105103.   Hence, ratio of gold and silver in the resulting alloy = 105/103.

Q: Althaf borrows Rs. 1500 from two moneylenders. He pays interest at the rate of 12% per annum for one loan and at the rate of 14% per annum for the other. The total interest he pays for the entire year is Rs. 186. How much does he borrow at the rate of 12% ? 2553 0

  • 1
    Rs. 300
    Correct
    Wrong
  • 2
    Rs. 400
    Correct
    Wrong
  • 3
    Rs. 1200
    Correct
    Wrong
  • 4
    Rs. 1100
    Correct
    Wrong
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Answer : 3. "Rs. 1200"
Explanation :

Answer: C) Rs. 1200 Explanation: Let Althaf lent Rs. A at 14% per year.Hence, Money lent at 12% = (1500-A);Given, total interest = Rs. 186.{(A x 14x 1)/100} + {[(1500-A) x 12 x 1/100]} = 186;14A/100 + (18000 -12A)/100 = 186;14A + 18000 - 12A = 186x100;2A = 18600-18000;A = 600/2 = Rs. 300.Hence, money lent at 12% = 1500-300 = Rs. 1200.

Q: At a dinner party every two guests used a bowl of rice between them, every three guests used a bowl of dal between them and every four used a bowl of meat between them. There were altogether 65 dishes. How many guests were present at the party ? 2550 0

  • 1
    60
    Correct
    Wrong
  • 2
    74
    Correct
    Wrong
  • 3
    82
    Correct
    Wrong
  • 4
    58
    Correct
    Wrong
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Answer : 1. "60"
Explanation :

Answer: A) 60 Explanation: Let, no. of rice bowl = xno. of dal bowl = yno. of meat bowl = z Then, x + y + z = 65 ....(1) Also given that, 2x = 3y = 4z substituting value of y & z in terms of x i.e. y = 2x/3 and z = x/2 in eq (1),We get x = 30. As 1 rice bowl is shared between 2 guests, Therefore, there are 60 guests.

Q: A man can row against the current three fourth of a kilometer in 15 min and returns same distance in 10 min, then ratio of his speed to that of current? 2543 0

  • 1
    5:1
    Correct
    Wrong
  • 2
    3:1
    Correct
    Wrong
  • 3
    4:1
    Correct
    Wrong
  • 4
    2:1
    Correct
    Wrong
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Answer : 1. "5:1"
Explanation :

Answer: A) 5:1 Explanation: Let the speed of the man in still water = p kmph Speed of the current = s kmph Now, according to the questions (p + s) x 10 = (p - s) x 15 2p + 2s = 3p - 3s => p : s = 5 : 1   Hence, ratio of his speed to that of current = 5:1.

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Answer : 1. "3:2"
Explanation :

Answer: A) 3:2 Explanation: Concentration of glucose are in the ratio = 12:35:45 Quantity of glucose taken from A = 1 liter out of 2 Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit Quantity of glucose taken from C = 0.8 lit So, total quantity of glucose taken from A,B and C = 3.6 lit So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit Ratio of glucose to alcohol = 3.6/2.4 = 3:2

Q: 5 men and 3 boys can together cultivate a 23 acre field in 4 days and 3 men and 2 boys together can cultivate a 7 acre field in 2 days. How many boys will be needed together with 7 men, if they cultivate 45 acre of field in 6 days. 2542 0

  • 1
    6
    Correct
    Wrong
  • 2
    4
    Correct
    Wrong
  • 3
    2
    Correct
    Wrong
  • 4
    3
    Correct
    Wrong
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Answer : 3. "2"
Explanation :

Answer: C) 2 Explanation: Let work done by 1 man in i day be m and Let work done by 1 boy in 1 day be b From the given data, 4(5m + 3b) = 23 20m + 12b = 23....(1) 2(3m + 2b) = 7 6m + 4b = 7 ....(2) By solving (1) & (2), we get m = 1, b = 1/4 Let the number of required boys = n 6(7 1 + n x 1/4) = 45 => n = 2.

Q: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 2540 0

  • 1
    18
    Correct
    Wrong
  • 2
    14
    Correct
    Wrong
  • 3
    22
    Correct
    Wrong
  • 4
    24
    Correct
    Wrong
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Answer : 2. "14"
Explanation :

Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14

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