Quantitative Aptitude Practice Question and Answer

Q: There are 15 lines in plane. How many intersections (Maximum) can be made ? 1442 0

  • 1
    55
    Correct
    Wrong
  • 2
    105
    Correct
    Wrong
  • 3
    215
    Correct
    Wrong
  • 4
    148
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2. "105"
Explanation :

Answer: B) 105 Explanation: First line will cut all other 14, similarly second will cut 13, and so onTotal = 14+13+12+11+10+9+8+7+6+5+4+3+2+1 = 105.

Q: An Engine length 1000 m moving at 10 m/s. A bird is flying from engine to end with 'x' m/s and coming back at '2x' m/s. Take total time of bird travelling as 187.5 s. Find x and 2x in km/hr ? 1492 0

  • 1
    21.4 and 42.8
    Correct
    Wrong
  • 2
    25.2 and 50.4
    Correct
    Wrong
  • 3
    31.4208 and 62.8416
    Correct
    Wrong
  • 4
    33.12 and 66.24
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "31.4208 and 62.8416"
Explanation :

Answer: C) 31.4208 and 62.8416 Explanation: Birds speeds in mtrs/sec is 'x' and '2x' .While flying from Engine to end, relative speed = (x+10) m/secfrom end to engine, flying speed = (2x - 10) mtr/secso 1000/(x+10) + 1000/(2x-10) = 187.5 secssolving it, we getso x = 8.728 m/sec and 2x= 17.456 m/sec x = 31.4208 km/hr and 2x = 62.8416 km/hr.

Q: Hemavathi gets 3 marks for each right sum and loses 2 marks for each wrong sum. He attempts 35 sums and obtains 60 marks. The number of sums attempted correctly is ? 1111 0

  • 1
    23
    Correct
    Wrong
  • 2
    24
    Correct
    Wrong
  • 3
    25
    Correct
    Wrong
  • 4
    26
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 4. "26"
Explanation :

Answer: D) 26 Explanation: Let, Hema attempted 'k' sum correctly, then k x 3 -2 x(35-k) = 605k = 130k = 26 so 26 correct sums.

Q: The sum of one-half, one-third and one-fourth of a number exceeds the number by 22. The number is 1145 0

  • 1
    264
    Correct
    Wrong
  • 2
    284
    Correct
    Wrong
  • 3
    215
    Correct
    Wrong
  • 4
    302
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "264"
Explanation :

Answer: A) 264 Explanation: Let the number be 'x'. Then, from given data x/2 + x/3 + x/4 = x+2213x/12 = x+22x = 264

Q: A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ? 1507 0

  • 1
    14.69 cm
    Correct
    Wrong
  • 2
    29.39 cm
    Correct
    Wrong
  • 3
    18.65 cm
    Correct
    Wrong
  • 4
    22.21 cm
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2. "29.39 cm"
Explanation :

Answer: B) 29.39 cm Explanation: Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms.   As speed is same, area of cross sections should be same.    Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12  i.e πR2 = 6πR12    Here R = R and R1 = 12/2 = 6    ⇒R2 = 6×6×6    R = 14.696    => D = X = 14.696 * 2 = 29.3938 cm.

Q: Population of a colony of mosquitoes is increasing by 20% per day. If the population on Monday was 3000, on which day of that week the population would be 5184 ? 1453 0

  • 1
    Thursday
    Correct
    Wrong
  • 2
    Friday
    Correct
    Wrong
  • 3
    Tuesday
    Correct
    Wrong
  • 4
    Monday
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "Thursday"
Explanation :

Answer: A) Thursday Explanation: Given monday population = 3000Per day 20% increase in population. Tuesday population = 3000 + 3000x20/100 = 3000 + 600 = 3600 Wednesday population =3600 + 3600x20/100 = 3600 + 720 = 4320 Thursday population = 4320 + 4320x20/100 = 4320 + 864 = 5184 So that day is Thursday.

Q: Two parallel chords on the same side of the centre of a circle are 5 cm apart. If the chords are 20 and 28 cm long, what is the radius of the circle? 973 0

  • 1
    14.69 cm
    Correct
    Wrong
  • 2
    15.69 cm
    Correct
    Wrong
  • 3
    18.65 cm
    Correct
    Wrong
  • 4
    16.42 cm
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2. "15.69 cm"
Explanation :

Answer: B) 15.69 cm Explanation: Draw the two chords as shown in the figure. Let O be the center of the circle. Draw OC perpendicular to both chords. That divides the two chords in half.So CD = 10 and AB = 14. Draw radii OA and OD, both equal to radius r.We are given that BC = 5, the distance between the two chords. LetOB = x. We use the Pythagorean theorem on right triangle ABO AO² = AB² + OB² r² = 14² + x² We use the Pythagorean theorem on right triangle DCO DO² = CD² + OC² We see that OC = OB+BC = x+5, so r² = 10² + (x+5)² So we have a system of two equations: r² = 14² + x² r² = 10² + (x+5)² Since both left sides equal r², set the right sidesequal to each other. 14² + x² = 10² + (x+5)² 196 + x² = 100 + x² + 10x + 25 196 = 125 + 10x 71 = 10x 7.1 = x r² = 14² + x² r² = 196 + (7.1)² r² = 196 + 50.41 r² = 246.41 r = √246.41 r = 15.69745202 cm

Q: An express train takes 4 seconds to enter tunnel which is 1 km long. If it is traveling at 108 km an hour, how long will it take to pass completely through the tunnel ? 1303 0

  • 1
    33 sec
    Correct
    Wrong
  • 2
    37.33 sec
    Correct
    Wrong
  • 3
    36.43 sec
    Correct
    Wrong
  • 4
    32 sec
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2. "37.33 sec"
Explanation :

Answer: B) 37.33 sec Explanation: Speed = 108 km/hrenter a tunnel,, means that the train covers a distance equal to its own lengthso (108 x 5/18) = x/4 where x= length of trainhence x = 120 mtrsto pass completely train has to travel a distance = (x + tunnel length) that is 1120 mtrs.so (1120/t) = (108x5/18)t = 37.33 sec

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully