Quantitative Aptitude Practice Question and Answer
8Q: The marked price of a Watch is Rs.8400. It is to be sold at Rs.6896 at two successive discounts. If the first discount is 12%, the second discount is ? 1479 05b5cc720e4d2b4197774f627
5b5cc720e4d2b4197774f627- 17.2 %false
- 29.14 %false
- 37.13 %false
- 46.709 %true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "6.709 %"
Explanation :
Answer: D) 6.709 % Explanation: (100-x)% of 88% of 8400 = 6896 => 100-x10088100x8400 = 6896 => x = 6.709%
Q: A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ? 2564 05b5cc720e4d2b4197774f613
5b5cc720e4d2b4197774f613- 145false
- 224false
- 342false
- 454true
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "54"
Explanation :
Answer: D) 54 Explanation: By trial and error method from the given options, as 54 - 45 = (1/11) x (45+54) = 99/11 = 9 Hence this satisfies the given conditions. Then the woman's husband age is 54.
Q: 12 year old Manish is three times as old as his brother Rajeev. How old will Manish be when he is twice as old as Rajeev ? 2016 05b5cc720e4d2b4197774f5f4
5b5cc720e4d2b4197774f5f4- 112 yrsfalse
- 214 yrsfalse
- 316 yrstrue
- 418 yrsfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "16 yrs"
Explanation :
Answer: C) 16 yrs Explanation: 12 year old Manish is three times as old as his brother Rajeev who must be 4 years old.Diff in ages = 8 years.when Rajeev will become 8 years old, Manish will be 16 yrs old and he will be twice as old as Rajeev.
Q: A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ? 1235 05b5cc720e4d2b4197774f5ea
5b5cc720e4d2b4197774f5ea- 145, 10false
- 210, 50false
- 39, 50true
- 450, 15false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "9, 50"
Explanation :
Answer: C) 9, 50 Explanation: Let the age of A = A, B = B and C = C From given A = 3B 4 years ago, C-4 = 2(A-4); After 4 years A + 4 = 31; A = 27;sub in above B, we get B = 9 C = 2(27 - 4) + 4 = 46 + 4 = 50 Hence B = 9yrs and C = 50yrs.
Q: Two bus tickets from city K to L and three tickets from city K to M cost Rs. 77, but three tickets from city K to L and two tickets from city K to M cost Rs. 73. What are the fares for cities L and M from K ? 1704 05b5cc720e4d2b4197774f5e0
5b5cc720e4d2b4197774f5e0- 1Rs. 13 and Rs. 17true
- 2Rs. 17 and Rs. 19false
- 3Rs. 23 and Rs. 17false
- 4Rs. 13 and Rs. 19false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "Rs. 13 and Rs. 17"
Explanation :
Answer: A) Rs. 13 and Rs. 17 Explanation: If fares for cities L and M from K are x and y respectively, then 2x + 3y = 77 or 6x + 9y = 231...(1)3x + 2y = 73 or 6x + 4y = 146...(2) subtracting 2 from 1, we get 5y = 85 y = Rs. 17 => x = Rs. 13
Q: Consider 5 independent Bernoulli’s trials each with probability of success p. If the probability of at least one failure is greater than or equal to 31/32 , then p lies in the interval ? 946 05b5cc71ee4d2b4197774f5c7
5b5cc71ee4d2b4197774f5c7- 1[1, 32]false
- 2(0, 1)false
- 3[1, 1/2]true
- 4(1, 1/2]false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "[1, 1/2]"
Explanation :
Answer: C) [1, 1/2] Explanation: Probability of atleast one failure= 1 - no failure > 31/32= 1 - P5 > 31/32= P5<1/32= p < 1/2Also p > 0Hence p lies in [0,1/2].
Q: A man saves Rs. 200 in each of the first three months of his service. In each of the subsequent months his saving increases by Rs. 40 more than the saving of immediately previous month. His total saving from the start of service will be Rs. 11040 after ? 1465 05b5cc71ee4d2b4197774f5b8
5b5cc71ee4d2b4197774f5b8- 119 monthsfalse
- 221 monthstrue
- 318 monthsfalse
- 420 monthsfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "21 months"
Explanation :
Answer: B) 21 months Explanation: Total savings = 200 + 200 + 200 + 240 + 280 + ... to n months = 11040 = 120 + 80 + 160 + 40 + 200 + 240 + ....n terms= 40 + 80 + 120 + 160 + 200 + 240 + ...n terms= n/2[2a + (n-1)d] + 80 + 40 = 11040= n/2[240 + (n-1)40] = 10920= n[6+n-1] = 546= n[n+5] = 546n = 21
Q: Three friends had dinner at a restaurant. When the bill was received, Akshitha paid 2/3 as much as Veena paid and Veena paid 1/2 as much as Lasya paid. What fraction of the bill did Veena pay ? 1294 05b5cc71ee4d2b4197774f5ae
5b5cc71ee4d2b4197774f5ae- 111/3false
- 22/13false
- 33/11true
- 413/4false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "3/11"
Explanation :
Answer: C) 3/11 Explanation: Let Veena paid x,so Akshitha paid 2x/3 , and Lasya paid 2x,So total bill paid is given byx+(2x/3) +2x = 1, we geti.e. x = 3/11