Quantitative Aptitude Practice Question and Answer

Q: One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture. 1955 0

  • 1
    27 %
    Correct
    Wrong
  • 2
    26 %
    Correct
    Wrong
  • 3
    29 %
    Correct
    Wrong
  • 4
    21 %
    Correct
    Wrong
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Answer : 1. "27 %"
Explanation :

Answer: A) 27 % Explanation: Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135  X = 27 So, required percentage of benzene = 27 %

Q: The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ? 1954 1

  • 1
    14th element
    Correct
    Wrong
  • 2
    9th element
    Correct
    Wrong
  • 3
    12th element
    Correct
    Wrong
  • 4
    7th element
    Correct
    Wrong
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Answer : 3. "12th element"
Explanation :

Answer: C) 12th element Explanation: If we consider the third term to be ‘x”The 15th term will be (x + 12d)6th term will be (x + 3d)11th term will be (x + 8d) and 13th term will be (x + 10d).Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.x + 9d will be the 12th term. Thus, 12th term of the A.P will be zero.

Q: Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes? 1951 0

  • 1
    5 kmph
    Correct
    Wrong
  • 2
    6 kmph
    Correct
    Wrong
  • 3
    7.5 kmph
    Correct
    Wrong
  • 4
    8 kmph
    Correct
    Wrong
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Answer : 1. "5 kmph"
Explanation :

Answer: A) 5 kmph Explanation: Let p be the speed of man in kmph According to the given data in the question, Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction => 20 x 10/60 = 8/60 (20 + p) => 200 = 160 + 8p => p = 40/8 = 5 kmph.

Q: From a bunch of flowers having 16 red roses and 14 white roses, four flowers have to be selected. In how many different ways can they be selected such that at least one red rose is selected? 1951 0

  • 1
    27405
    Correct
    Wrong
  • 2
    26584
    Correct
    Wrong
  • 3
    26585
    Correct
    Wrong
  • 4
    27404
    Correct
    Wrong
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Answer : 4. "27404"
Explanation :

Answer: D) 27404 Explanation: Given total 16 Red roses and 14 White roses = 30 roses   Four flowers have to be selected from 30 i.e,  C430= 27405 Ways    Now, atleast one Red rose is selected i.e, 27405(total) - 1(all four are white roses)  = 27404 ways.

Q: The capacity of a tank is 2400 m3.  A pump can be used both for filling and emptying the tank.  The emptying capacity of the pump is 10 m3/minute higher than its filling capacity. And also, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump. 1950 0

  • 1
    46 cub.m/min
    Correct
    Wrong
  • 2
    44 cub.m/min
    Correct
    Wrong
  • 3
    48 cub.m/min
    Correct
    Wrong
  • 4
    50 cub.m/min
    Correct
    Wrong
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Answer : 4. "50 cub.m/min"
Explanation :

Answer: D) 50 cub.m/min Explanation: Let filling capacity of the pump be 'F' m3/min Then, the filling capacity of the pump will be (F + 10) m3/min From the given data, 2400F - 2400F+10= 8⇒ 2400 F+10-FF(F+10) =8⇒ F2 + 10F - 3000 = 0⇒ F = 50 m3/min

Q: 5% of a number is 25% more than another number. The difference between the numbers is 96. Then find the value of the numbers? 1949 0

  • 1
    102 & 6
    Correct
    Wrong
  • 2
    99 & 3
    Correct
    Wrong
  • 3
    104 & 8
    Correct
    Wrong
  • 4
    100 & 4
    Correct
    Wrong
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Answer : 4. "100 & 4"
Explanation :

Answer: D) 100 & 4 Explanation: Let the first number be x and the second number be y. Given 5% of x = (25% of y) + y => 5x/100 = 5y/4 => x = 25y ......(1) and also given that, x - y = 96 => x = 96 + y .....(2) From (1)&(2) 25y = 96 + y => 24y = 96 => y = 4 From (1) x = 96 + 4 = 100 Hence, the numbers are 100 & 4.

Q: In what ratio must wheat at Rs. 3.20/kg be mixed with wheat at Rs. 2.90/kg so that the mixture be worth Rs. 3/kg? 1946 0

  • 1
    1:2
    Correct
    Wrong
  • 2
    3:2
    Correct
    Wrong
  • 3
    2:1
    Correct
    Wrong
  • 4
    2:3
    Correct
    Wrong
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Answer : 3. "2:1"
Explanation :

Answer: C) 2:1 Explanation: Given rate of wheat at cheap = Rs. 2.90/kg Rate of wheat at cost = Rs. 3.20/kg Mixture rate = Rs. 3/kg Ratio of mixture =            2.90                              3.20                               3 (3.20 - 3 = 0.20)            (3 - 2.90 = 0.10)   0.20 : 0.10 = 2:1   Hence, wheat at Rs. 3.20/kg be mixed with wheat at Rs. 2.90/kg in the ratio of 2:1, so that the mixture be worth Rs. 3/kg.

Q: Find out the wrong term in the given series of numbers ?6, 15, 35, 77, 165, 221 1946 0

  • 1
    35
    Correct
    Wrong
  • 2
    165
    Correct
    Wrong
  • 3
    221
    Correct
    Wrong
  • 4
    77
    Correct
    Wrong
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Answer : 2. "165"
Explanation :

Answer: B) 165 Explanation: The given series follow the rule that : Multiplying consecutive prime numbers2,3,5,7,11,13,17,19....2x3 = 63x5 = 155x7 = 357x11 = 7711x13 = 14313x17 = 221So, the wrong term is 165.

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