Quantitative Aptitude Practice Question and Answer

Q: A sequence of natural number 2,3,5,6,10. Such that no square and no cube occurs in the term. Find the 300th term of sequence ? 1039 0

  • 1
    322
    Correct
    Wrong
  • 2
    319
    Correct
    Wrong
  • 3
    321
    Correct
    Wrong
  • 4
    320
    Correct
    Wrong
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Answer : 4. "320"
Explanation :

Answer: D) 320 Explanation: 1 to 300 = 300 numbers squares btwn 1 to 300 = 1,4,9,16,25,36,49.....289 i.e, total 17cubes = 1,8,27,64,125,216 i.e, 5 now 1 and 64 are common so total numbers that should be removed ( 17+5-2= 20 )total 20 term removed so 300th term would be 320

Q: Sambhu buys rice at Rs. 10/kg and puts a price tag on it so as to earn a profit of 20%. However, his faulty balance shows 1000 gm when it is actually 800 gm. What is his actual gain percentage ? 1312 0

  • 1
    50%
    Correct
    Wrong
  • 2
    25%
    Correct
    Wrong
  • 3
    75%
    Correct
    Wrong
  • 4
    60%
    Correct
    Wrong
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Answer : 1. "50%"
Explanation :

Answer: A) 50% Explanation: CP of 1000gm = Rs. 10SP of 800gm = Rs. 12SP of 1000gm =12x1000/800 = Rs. 15 Now take 1000gm as reference to calculate profit.Profit=SP-CP=15-10=Rs. 5Profit % = 5x100/10 = 50%

Q: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs. 5000 ? 3966 0

  • 1
    Rs. 5500
    Correct
    Wrong
  • 2
    Rs. 6000
    Correct
    Wrong
  • 3
    Rs. 6200
    Correct
    Wrong
  • 4
    Rs. 6350
    Correct
    Wrong
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Answer : 2. "Rs. 6000"
Explanation :

Answer: B) Rs. 6000 Explanation: The wages of labourers in a factory increases in the ratio 22:25 and there was a reduction in the number of labourers in the ratio 15:11. Find the original wage bill if the present bill is Rs 5000 ?Ratio of increase of wages = 22:25Ratio of decrease of labourers = 15:11Compound ratio of wages of labourers = 22 x 15 : 25 x 11 = 330:275Final bill = Rs. 5000For 275 ratio wages = Rs. 5000For 1 ratio wages = 5000/275For 330 ratio wages = 5000/275 x 330 = Rs. 6000

Q: What was the day on 2nd Jan 1901 ? 3629 0

  • 1
    Tuesday
    Correct
    Wrong
  • 2
    Wednesday
    Correct
    Wrong
  • 3
    Monday
    Correct
    Wrong
  • 4
    Thursday
    Correct
    Wrong
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Answer : 2. "Wednesday"
Explanation :

Answer: B) Wednesday Explanation: 2nd Jan 1901 means(1900 years and 2 day)Now, 1600 years have 0 odd day300 years have 1 odd day2 days has 2 odd dayTotal no. of odd days = 0 + 1 + 2 = 3 daysHence, the day on 2nd Jan 1901 was Wednesday.

Q: There are 41 students in a class, number of girls is one more than number of guys. we need to form a team of four students. all four in the team cannot be from same gender. number of girls and guys in the team should NOT be equal. How many ways can such a team be made ? 1501 0

  • 1
    49450
    Correct
    Wrong
  • 2
    50540
    Correct
    Wrong
  • 3
    46587
    Correct
    Wrong
  • 4
    52487
    Correct
    Wrong
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Answer : 2. "50540"
Explanation :

Answer: B) 50540 Explanation: Given G + B= 41 and B = G-1 Hence, G = 21 and B = 20Now we have 2 options, 1G and 3M (or) 3G and 1M(2G and 2M or 0G and 4M or 4G and oM are not allowed),   Total : C121×C320+C321×C120= 50540 ways.

Q: The difference of two numbers is 14. Their LCM and HCF are 441 and 7. Find the two numbers ? 2631 0

  • 1
    63 and 49
    Correct
    Wrong
  • 2
    64 and 48
    Correct
    Wrong
  • 3
    62 and 46
    Correct
    Wrong
  • 4
    64 and 49
    Correct
    Wrong
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Answer : 1. "63 and 49"
Explanation :

Answer: A) 63 and 49 Explanation: Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y Difference = 14 => 7x - 7y = 14=> x - y = 2 product of numbers = product of their hcf and lcm=> 7x * 7y = 441 * 7=> x * y = 63 Now, we havex * y = 63 , x - y = 2=> x = 9 , y = 7 The numbers are 7x and 7y=> 63 and 49

Q: If 1/a+1/b+1/c = 1/(a+b+c) where a+b+c not equals '0', abc not equals '0', What is the value of (a+b) (b+c) (a+c) ? 1340 0

  • 1
    3
    Correct
    Wrong
  • 2
    2
    Correct
    Wrong
  • 3
    1
    Correct
    Wrong
  • 4
    0
    Correct
    Wrong
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Answer : 4. "0"
Explanation :

Answer: D) 0 Explanation: Let assume the value of a,b &c that will satisfy the equation.so a=1,b=1,c= -1 or a=1,b= -1 &c=1 or a= -1,b=1,c=1here all three cases satisfy the equationassume any one a=1,b=1,c= -1 Hence (a+b)(b+c)(c+a)=(1+1)(1-1)(-1+1) = 0

Q: There are 3 bags, in 1st there are 9 Mangoes, in 2nd 8 apples & in 3rd 6 bananas. There are how many ways you can buy one fruit if all the mangoes are identical, all the apples are identical, & also all the Bananas are identical ? 1297 0

  • 1
    23
    Correct
    Wrong
  • 2
    432
    Correct
    Wrong
  • 3
    22
    Correct
    Wrong
  • 4
    431
    Correct
    Wrong
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Answer : 1. "23"
Explanation :

Answer: A) 23 Explanation: As in this problem , buying any fruit is different case , as buying apple is independent from buying banana. so ADDITION rule will be used.   C19+C18+C16 = 23 will be answer.

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