Answer: C) 186 Explanation: The given number series is 3  24  186  1008  5040  20160 Here  the given series follows a pattern that, 3 3 x 8 = 24 24 x 7 = 168 not 186 168 x 6 = 1008 1008 x 5 =  5040 5040 x 4 = 20160   Hence the Odd One in the number series is 186.

Answer: D) 3 pm Explanation: Work done by P and Q in the first two hours, working alternately = First hour P + Second hour Q ⇒14+112=13 work is completed in 2 hours Then, the total time required to complete the work by P and Q working alternately=2 x 3= 6hours Thus, work will be completed at 3pm.

Answer: B) Option B Explanation: Man walked 6 km at 1.5 kmph, again he walked 8 km at speed of 2 kmph and 40 km at a speed of 8kmphtime taken indivisually: => 6/1.5 = 4 m=> 8/2 = 4 m=> 40/8 = 5 m   Average speed of man= total distance/ total time=> 54/13 = 4213 kmph

Answer: B) 30 kmph Explanation: Let the speed of the faster train be 'S' kmph   Then speed of the slower train will be '(S-5)' kmph   Time taken by faster train = 350/S hrs   Time taken by slower train = 350/(S-5) hrs  350s-5 - 350s = 2 hrs 20 min = 213 = 73   => S = 30 km/hr.

Answer: D) 64 Explanation: The given number series follows a pattern that 196, 169, 144, 121, 100, 81, ?     -27  -25   -23   -21  -19  -17   => 81 - 17 = 64 Therefore, the series is 196, 169, 144, 121, 100, 81, 64.

Answer: C) 12 Explanation: we can do this by trial and error method. Putting x = 2,we get 2²(2² - 1) = 12.checking with other integers, the above equation always gives a value which is a multiple of 12,So, x²(x² - 1) is always divisible by 12.

Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.