Quantitative Aptitude Practice Question and Answer
8Q: Three strategies P, Q and R have been initiated for cost cutting in a company producing respectively 20%, 30% and 10% savings. Assuming that they operate independently, what is the net saving achieved ? 1876 05b5cc73ae4d2b4197774f8dd
5b5cc73ae4d2b4197774f8dd- 149.6%true
- 250.4%false
- 333.67%false
- 466.66%false
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Answer : 1. "49.6%"
Explanation :
Answer: A) 49.6% Explanation: As these three strategies P, Q and R are independent so these will cut cost one after the other.If initial cost is Rs 100, then20% cost is cut after initializing strategy P, then cost will remain 80% = 80further 30% cost is cut after strategy Q, then cost will remain 70% of 80 = 56further 10% cost is cut after strategy R, then cost will remain 90% of 56 = 50.4 Thus final cost remains 50.4 % of the original cost. Hence net saving is 100 - 50.4 = 49.6 %.
Q: If (2a + 3b)/(5a - 3b) = 23/5 , then the value of ba is ? 1872 05b5cc761e4d2b4197774fd39
5b5cc761e4d2b4197774fd39- 15false
- 24false
- 320true
- 428false
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Answer : 3. "20"
Explanation :
Answer: C) 20 Explanation: Given (2a + 3b)/(5a - 3b) = 23/5 => 10a + 15b = 115a - 69b=> 105a = 84b => 5a = 4b a/b = 4/5 => a=4 & b=5=> bxa = 5x4 = 20.
Q: A passenger train covers the distance between station K and L, 40 minutes faster than a goods train. Find this distance between K and L if the average speed of the passenger train is 50 km/h and that of goods train is 30 km/h? 1868 05b5cc6b4e4d2b4197774d4c5
5b5cc6b4e4d2b4197774d4c5- 150 kmstrue
- 248 kmsfalse
- 346 kmsfalse
- 444 kmsfalse
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Answer : 1. "50 kms"
Explanation :
Answer: A) 50 kms Explanation: Let the distance be 'd' kms. According to the given data, d30 - d50 = 4060 hrs=> 6d = 300=> d = 50 kms.
Q: Given that 100.48 = x, 100.70 = y and xz = y2, then the value of z is close to ___ ? 1866 05b5cc6bee4d2b4197774d983
5b5cc6bee4d2b4197774d983- 13.7false
- 22.7false
- 33.6false
- 42.9true
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Answer : 4. "2.9"
Explanation :
Answer: D) 2.9 Explanation: xz = y2 10(0.48z) = 10(2 x 0.70) = 101.40 0.48z = 1.40 z = 140/18 = 35/12 = 2.9 (approx.)
Q: Rajitha's present age is three years less than twice her age 12 years ago. Also, the ratio of Raj's present age to Rajitha's present age is 4:9. What will be Raj's age after 5 years ? 1866 05b5cc736e4d2b4197774f82d
5b5cc736e4d2b4197774f82d- 117 yrstrue
- 216 yrsfalse
- 319 yrsfalse
- 421 yrsfalse
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Answer : 1. "17 yrs"
Explanation :
Answer: A) 17 yrs Explanation: Let the present age of Raj and Rajitha be 4x and 9x.Then, according to question,9x = 2(9x-12)-3 => 9x = 27 => x = 3Raj's present age = 4x = 12yrs, After 5 years Raj's age will be 12 + 5 = 17 yrs.
Q: A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is : 1865 05b5cc783e4d2b419777501e7
5b5cc783e4d2b419777501e7- 19.5 km/hrfalse
- 210 km/hrtrue
- 310.5 km/hrfalse
- 411 km/hrfalse
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Answer : 2. "10 km/hr"
Explanation :
Answer: B) 10 km/hr Explanation: Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr. Therefore, Man's rate against the current = (12.5 - 2.5) = 10 km/hr.
Q: The compound interest earned by Sunil on a certain amount at the end of two years at the rate of 8% p.a. was Rs.2828.80. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned ? 1864 05b5cc6dee4d2b4197774ea74
5b5cc6dee4d2b4197774ea74- 1Rs. 11828.80false
- 2Rs. 19828.80true
- 3Rs. 9828.80false
- 4Rs. 19328.80false
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Answer : 2. "Rs. 19828.80"
Explanation :
Answer: B) Rs. 19828.80 Explanation: Let the sum be Rs. P P{ 1+81002- 1 } = 2828.80 It is in the form of a2-b2 = a+ba-b P(8/100)(2 + 8/100) = 2828.80 P = 2828.80 / (0.08)(2.08) = 1360/0.08 = 17000 Principal + Interest = Rs. 19828.80
Q: Two trains 85 m and 75 m long are running in same direction with speeds of 62 km/hr and 44 km/hr respectively. In what time will the first train cross the second train ? 1862 15b5cc783e4d2b41977750214
5b5cc783e4d2b41977750214- 122 secfalse
- 232 sectrue
- 342 secfalse
- 452 secfalse
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Answer : 2. "32 sec"
Explanation :
Answer: B) 32 sec Explanation: Given that, 1st train speed = 62 km/hr 2nd train speed = 44 km/hr Hence the relative speed of two trains is : 62-44 = 18 km/hr = 18×518 m/s = 5 m/s. There fore, the first train crosses the second train i.e (85+75)mts of distance with a speed of 5m/s in, time = distancespeed = 85+755 = 32 sec.