Quantitative Aptitude Practice Question and Answer
8Q: In what ratio must wheat at Rs. 3.20/kg be mixed with wheat at Rs. 2.90/kg so that the mixture be worth Rs. 3/kg? 2154 05b5cc639e4d2b4197774baa0
5b5cc639e4d2b4197774baa0- 11:2false
- 23:2false
- 32:1true
- 42:3false
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Answer : 3. "2:1"
Explanation :
Answer: C) 2:1 Explanation: Given rate of wheat at cheap = Rs. 2.90/kg Rate of wheat at cost = Rs. 3.20/kg Mixture rate = Rs. 3/kg Ratio of mixture = 2.90 3.20 3 (3.20 - 3 = 0.20) (3 - 2.90 = 0.10) 0.20 : 0.10 = 2:1 Hence, wheat at Rs. 3.20/kg be mixed with wheat at Rs. 2.90/kg in the ratio of 2:1, so that the mixture be worth Rs. 3/kg.
Q: Find the Odd One Out? 3 24 186 1008 5040 20160 2153 05b5cc6a8e4d2b4197774ceac
5b5cc6a8e4d2b4197774ceac- 124false
- 220160false
- 3186true
- 45040false
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Answer : 3. "186"
Explanation :
Answer: C) 186 Explanation: The given number series is 3 24 186 1008 5040 20160 Here the given series follows a pattern that, 3 3 x 8 = 24 24 x 7 = 168 not 186 168 x 6 = 1008 1008 x 5 = 5040 5040 x 4 = 20160 Hence the Odd One in the number series is 186.
Q: The sum of three consecutive odd numbers is 93. What is the middle number? 2150 05b5cc6b7e4d2b4197774d5e7
5b5cc6b7e4d2b4197774d5e7- 131true
- 233false
- 329false
- 427false
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Answer : 1. "31"
Explanation :
Answer: A) 31 Explanation: Let the three consecutive odd numbers be x, x+2, x+4 Then, x + x + 2 + x + 4 = 93 => 3x + 6 = 93 => 3x = 87 => x = 29 => 29, 31, 33 are three consecutive odd numbers. Therefore, the middle number is 31.
Q: Dot cabs company provides cabs for software employees. The company has 8 Swift dzires, 6 Scorpios, 7 Innovas and few small cars. If Swift dzire makes one fourth of the total fleet, how many small cars are there in the company ? 2149 05b5cc741e4d2b4197774f9ea
5b5cc741e4d2b4197774f9ea- 19false
- 210false
- 311true
- 412false
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Answer : 3. "11"
Explanation :
Answer: C) 11 Explanation: Given the company has 8 SD + 6 SRP + 7 IN = 21 cars + 'x' small cars.Given SD makes 1/4 th of the total fleet.=> 8 = 1/4 (21 + x)=> 32 = 21 + x=> x = 11 Therefore, the company has 11 small cars.
Q: A man saves Rs. 200 in each of the first three months of his service. In each of the subsequent months his saving increases by Rs. 40 more than the saving of immediately previous month. His total saving from the start of service will be Rs. 11040 after ? 2148 05b5cc71ee4d2b4197774f5b8
5b5cc71ee4d2b4197774f5b8- 119 monthsfalse
- 221 monthstrue
- 318 monthsfalse
- 420 monthsfalse
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Answer : 2. "21 months"
Explanation :
Answer: B) 21 months Explanation: Total savings = 200 + 200 + 200 + 240 + 280 + ... to n months = 11040 = 120 + 80 + 160 + 40 + 200 + 240 + ....n terms= 40 + 80 + 120 + 160 + 200 + 240 + ...n terms= n/2[2a + (n-1)d] + 80 + 40 = 11040= n/2[240 + (n-1)40] = 10920= n[6+n-1] = 546= n[n+5] = 546n = 21
Q: Simplification the following equations
2147 05d4a92db0c56ef19ba1dc4b3
5d4a92db0c56ef19ba1dc4b3- 12955.5false
- 22905.5true
- 32590.5false
- 42905.5false
- 5None of thesefalse
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Answer : 2. "2905.5"
Q: If (2a + 3b)/(5a - 3b) = 23/5 , then the value of ba is ? 2147 05b5cc761e4d2b4197774fd39
5b5cc761e4d2b4197774fd39- 15false
- 24false
- 320true
- 428false
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Answer : 3. "20"
Explanation :
Answer: C) 20 Explanation: Given (2a + 3b)/(5a - 3b) = 23/5 => 10a + 15b = 115a - 69b=> 105a = 84b => 5a = 4b a/b = 4/5 => a=4 & b=5=> bxa = 5x4 = 20.
Q: 88 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be ? 2147 05b5cc723e4d2b4197774f659
5b5cc723e4d2b4197774f659- 1112 mtsfalse
- 284 mtstrue
- 396 mtsfalse
- 4108 mtsfalse
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Answer : 2. "84 mts"
Explanation :
Answer: B) 84 mts Explanation: Vol of silver = πR2h = 66 C.C Given D= 1mm => R = D/2 = 1/20 cm => 227×1202×h = 66 = 66 x 400 x (7/22) = 8400 cm = 84 mtrs.