Quantitative Aptitude Practice Question and Answer

Q: Solve the equation 122x+1 = 1 ? 4049 0

  • 1
    -1/2
    Correct
    Wrong
  • 2
    1/2
    Correct
    Wrong
  • 3
    1
    Correct
    Wrong
  • 4
    -1
    Correct
    Wrong
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Answer : 1. "-1/2"
Explanation :

Answer: A) -1/2 Explanation: Rewrite equation as 122x+1 = 120   Leads to 2x + 1 = 0    Solve for x : x = -1/2

Q: In 16 minutes, the minute hand gains over the hour hand by - 15487 0

  • 1
    16 deg
    Correct
    Wrong
  • 2
    80 deg
    Correct
    Wrong
  • 3
    88 deg
    Correct
    Wrong
  • 4
    94 deg
    Correct
    Wrong
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Answer : 3. "88 deg"
Explanation :

Answer: C) 88 deg Explanation: In one hour, the minute hand gains 330° over the hour hand. i.e., 60 minute, the minute hand gains 330° over the hour hand. ∴ In 16 minutes, the minute hand gain over the hour hand by

Q: Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 30% profit ? 2015 0

  • 1
    Rs. 17.80
    Correct
    Wrong
  • 2
    Rs. 16.30
    Correct
    Wrong
  • 3
    Rs. 14
    Correct
    Wrong
  • 4
    Rs. 15.40
    Correct
    Wrong
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Answer : 2. "Rs. 16.30"
Explanation :

Answer: B) Rs. 16.30 Explanation: C.P. of 50 kg wheat = (30 * 11.50 + 20 * 14.25) = Rs. 630. S.P. of 50 kg wheat = 130% of Rs. 630 = 130/100 * 630 = Rs. 819. S.P. per kg = 819/50 = Rs. 16.38 = 16.30.

Q: One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill tank in 36 min, then the slower pipe alone will be able to fill the tank in ? 1619 0

  • 1
    85 min
    Correct
    Wrong
  • 2
    92 min
    Correct
    Wrong
  • 3
    187 min
    Correct
    Wrong
  • 4
    144 min
    Correct
    Wrong
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Answer : 4. "144 min"
Explanation :

Answer: D) 144 min Explanation: Let the slower pipe alone fill the tank in x min. Then, faster pipe will fill it in x/3 min. 1/x + 3/x = 1/36  4/x = 1/36 => x = 144 min.

Q: A rectangular lawn of dimensions 80 m x 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m ? 1106 0

  • 1
    Rs. 3600
    Correct
    Wrong
  • 2
    Rs. 3800
    Correct
    Wrong
  • 3
    Rs. 3900
    Correct
    Wrong
  • 4
    Rs. 3700
    Correct
    Wrong
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Answer : 3. "Rs. 3900"
Explanation :

Answer: C) Rs. 3900 Explanation: Area = (l + b – d) d = (80 + 60 – 10)10 => 1300 sq.mts => 1300 x 3 = Rs.3900

Q: Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction ? 3448 0

  • 1
    2 9/7 km
    Correct
    Wrong
  • 2
    3 7/5 km
    Correct
    Wrong
  • 3
    1 3/4 km
    Correct
    Wrong
  • 4
    4 3/8 km
    Correct
    Wrong
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Answer : 4. "4 3/8 km"
Explanation :

Answer: D) 4 3/8 km Explanation: Relative Speed = 5 ¾ - 4 ½ = 1 ¼ Time = 3 ½ h. Distance = 5/4 x 7/2 = 35/8 = 4 3/8 km.

Q: Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 m x 5 m when 10% of its volume is occupied by concrete ? 1083 0

  • 1
    6000
    Correct
    Wrong
  • 2
    5400
    Correct
    Wrong
  • 3
    3800
    Correct
    Wrong
  • 4
    4700
    Correct
    Wrong
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Answer : 1. "6000"
Explanation :

Answer: A) 6000 Explanation: Let 'B' be the nuber of bricks. => 10 x 4/100 x 5 x 90/100 = 25/100 x 15/100 x 8/100 x B => 10 x 20 x 90 = 15 x 2 x B => B = 6000

Q: Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is : 1180 0

  • 1
    83
    Correct
    Wrong
  • 2
    89
    Correct
    Wrong
  • 3
    85
    Correct
    Wrong
  • 4
    79
    Correct
    Wrong
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Answer : 3. "85"
Explanation :

Answer: C) 85 Explanation: Since the numbers are co-prime, they contain only 1 as the common factor.Also, the given two products have the middle number in common.So, middle number = H.C.F of 551 and 1073 = 29;First number = 551/29 = 19Third number = 1073/29 = 37.Required sum = 19 + 29 + 37 = 85.

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