Answer: D) 25% Explanation: Here, k = 7 and l = 28Therefore, first number = klx100 % of second number = 7/28 x 100% of second number = 25% of second number.

Answer: B) 20 min Explanation: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages. Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr. stoppage time = 20/60 hrs = 20 min.

Answer: C) 25 Explanation: a+b=5   ...(1)    and    3a+2b=20 ...(2)   Multiplying (1) by 2 and subtracting from (2), we get : a=10.   Putting a=10 in (1), we get : b=-5   Therefore,   (3a+b) = 3 x 10+(-5)=30-5=25.

Answer: B) 42 : 625 Explanation: 6.72/100 = 672/10000 = 42/625

Answer: C) Rs.2000 Explanation: Let money invested by Raghu = Rs. xMoney invested by Trishul = 9/10 x = 0.9xMoney invested by Vishal = 9/10x * 110/100 = 0.99xAlso, x+0.9x+0.99x = 5780= x= 5780/2.89 = 2000 Therefore, amount invested by Raghu is Rs. 2000.

Answer: A) 5 kmph Explanation: Speed of the boat downstream  s=a/t= 60/3 = 20 kmph Speed of the boat upstream s= d/t = 30/3= 10 kmph   Therefore,  The speed of the stream = speed of downstream - speed of upstream2=5 kmph

Answer: A) Rs. 13 and Rs. 17 Explanation: If fares for cities L and M from K are x and y respectively, then 2x + 3y = 77 or 6x + 9y = 231...(1)3x + 2y = 73 or 6x + 4y = 146...(2) subtracting 2 from 1, we get 5y = 85 y = Rs. 17 => x = Rs. 13

Answer: A) Rs. 20 Explanation: Let the original price of rice be Rs. x Let rice a man can buy for Rs. 500 at rs. x/kg be = R kgs From given data, for Rs. 500 x ---- R kgs (x + 25x/100) ---- (R - 5) kgs => Rx = (R - 5)(x + 25x/100) => Rx = (R - 5)(125x/100) => 100Rx = 125Rx - 625x => R = 25 So at rate of Rs. x/kg, man get 25 kgs for Rs. 500 => x = 500/25 = Rs. 20