Quantitative Aptitude Practice Question and Answer
8Q: The marked price of a Watch is Rs.8400. It is to be sold at Rs.6896 at two successive discounts. If the first discount is 12%, the second discount is ? 1783 05b5cc720e4d2b4197774f627
5b5cc720e4d2b4197774f627- 17.2 %false
- 29.14 %false
- 37.13 %false
- 46.709 %true
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Answer : 4. "6.709 %"
Explanation :
Answer: D) 6.709 % Explanation: (100-x)% of 88% of 8400 = 6896 => 100-x10088100x8400 = 6896 => x = 6.709%
Q: Twenty men can do a work in eighteen days. Eighteen women can complete the same work in fifteen days. What is the ratio between the capacity of a woman and a man ? 1783 05b5cc774e4d2b4197775002a
5b5cc774e4d2b4197775002a- 14:5false
- 23:4false
- 34:3true
- 42:3false
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Answer : 3. "4:3"
Explanation :
Answer: C) 4:3 Explanation: (20 x 18) men can complete the work in in one day. one man's one day work = 1/360 (18 x 15) women can complete the work in 1 day 1 woman's one day work = 1/270 So, required ratio = 1270:1360= 4:3
Q: There is 50% increase in an amount in 5 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate ? 1782 05b5cc767e4d2b4197774fe01
5b5cc767e4d2b4197774fe01- 1Rs. 5422false
- 2Rs. 5489false
- 3Rs. 3972true
- 4Rs. 6145false
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Answer : 3. "Rs. 3972"
Explanation :
Answer: C) Rs. 3972 Explanation: Let p = Rs. 100. Then, S.I is Rs. 50 and time = 5 years. ∴ R = 100×50100×5= 10% p.a. Now, p = Rs. 12,000 , T = 3 years and R = 10% p.a. C.I. = Rs. 12000×1+101003-1= Rs. 3972
Q: The Simple interest accrued on an amount of Rs. 2,500 at the end of six years is Rs.1875. What would be the simple interest accrued on an amount of Rs. 6875 at the same rate and Same period? 1781 05b5cc7c7e4d2b41977750d78
5b5cc7c7e4d2b41977750d78- 1Rs. 4,556.5false
- 2Rs. 5,025.25false
- 3Rs.5,245.5false
- 4None of thesetrue
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Answer : 4. "None of these"
Explanation :
Answer: D) None of these Explanation:
Q: Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ? 1779 05b5cc74fe4d2b4197774fb21
5b5cc74fe4d2b4197774fb21- 179true
- 277false
- 376false
- 473false
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Answer : 1. "79"
Explanation :
Answer: A) 79 Explanation: Assuming Sripad has scored the least marks in subject other than science,Then the marks he could secure in other two are 58 each.Since the average mark of all the 3 subject is 65.i.e (58+58+x)/3 = 65116 + x = 195x = 79 marks. Therefore, the maximum marks he can score in maths is 79.
Q: If 25a + 25b = 115, then what is the average of a and b? 1777 05b5cc7c7e4d2b41977750daf
5b5cc7c7e4d2b41977750daf- 14.6false
- 23.4false
- 32.5false
- 4None of thesetrue
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Answer : 4. "None of these"
Explanation :
Answer: D) None of these Explanation:
Q: Three friends Rudra, Siva and Anvesh start to run around a circular stadium. They complete a revolution in 24, 36 and 30 seconds respectively. After how many minutes will they meet at the starting point ? 1776 05b5cc6c2e4d2b4197774dbb4
5b5cc6c2e4d2b4197774dbb4- 160false
- 2120false
- 3360false
- 46true
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Answer : 4. "6"
Explanation :
Answer: D) 6 Explanation: For this we have to find the LCM of 24, 36 and 30 LCM of 24, 36 and 30 = 360 sec 360/60 min = 6 minutes.
Q: Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ? 1771 05b5cc6c7e4d2b4197774de6e
5b5cc6c7e4d2b4197774de6e- 1108false
- 2107false
- 3109true
- 4110false
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Answer : 3. "109"
Explanation :
Answer: C) 109 Explanation: From given data, R : M = 5 : 7 M : A = 5 : 7 R : M : A = 25 : 35 : 49 25 + 35 + 49 = 109