Quantitative Aptitude Practice Question and Answer
8Q: If 6 years are subtracted from the present age of Arun and the remainder is divided by 18, then the present age of his grandson Gokul is obtained. If Gokul is 2 years younger to Madan whose age is 5 years, then what is the age of Arun ? 1526 05b5cc71be4d2b4197774f53a
5b5cc71be4d2b4197774f53a- 172 yearsfalse
- 254 yearsfalse
- 360 yearstrue
- 447 yearsfalse
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Answer : 3. "60 years"
Explanation :
Answer: C) 60 years Explanation: Let the Present age of arun is xGokul's age = 5-2 = 3x-6/18 = 3x-6 = 54x = 60Arun's present age = 60 years
Q: There are 209 doctors and nurses in a hospital. If the ratio of the doctors to the nurses is 11 : 8, then how many nurses are there in the hospital? 1525 05b5cc761e4d2b4197774fd44
5b5cc761e4d2b4197774fd44- 188true
- 296false
- 3108false
- 4121false
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Answer : 1. "88"
Explanation :
Answer: A) 88 Explanation: Given,The ratio of the doctors to the nurses is 11 : 8Number of nurses = 8/19 x 209 = 88.
Q: Arun has certain number of books. It is not less than 15 and not more than 30. If he wants to give these books equally to 2 of his friends, then 1 book will remain. If he wants to give these books equally to 3 of his friends, then 2 books will remain. If he wants to give these books equally to 4 of his friends, then 3 books will remain. What is the number of books he had ? 1524 05b5cc718e4d2b4197774f4a4
5b5cc718e4d2b4197774f4a4- 119false
- 223true
- 317false
- 415false
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Answer : 2. "23"
Explanation :
Answer: B) 23 Explanation: If he wants to give these books equally to 2 of his friends, then 1 book will remain, it means possible number of books = 15,17,19,21,23,25,27,29If he wants to give these books equally to 3 of his friends, then 2 books will remain, it means possible number of books = 17,20,23,26,29If he wants to give these books equally to 4 of his friends, then 3 book will remain, it means possible number of books = 15,19,23,27common number is only 23 so it will be answer
Q: The series of differences between consecutive prime numbers is represented as Cp1, Cp2, Cp3, .... Cpn , Whare Cp1 is the difference between the second and the first prime number. Find the sum of series when n = 23, given that the 23rd prime number is 83 ? 1521 05b5cc6fbe4d2b4197774f09f
5b5cc6fbe4d2b4197774f09f- 187true
- 281false
- 383false
- 485false
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Answer : 1. "87"
Explanation :
Answer: A) 87 Explanation: Cp1 = p2 - p1 , Cp2 = p3 - p2 ......Cp23 = p24 - p23Sum of series = (p2-p1) + (p3-p2) + .....(p23-p22) + (p24-p23)All terms get cancelled, except p1 = 2 and p24 = 89 So Sum = -p1 + p24Sum of series = -2 + 89 = 87
Q: Find the ratio of the areas of the incircle and circumcircle of a square ? 1520 05b5cc77fe4d2b419777501c9
5b5cc77fe4d2b419777501c9- 11 : 4false
- 24 : 1false
- 32 : 1false
- 41 : 2true
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Answer : 4. "1 : 2"
Explanation :
Answer: D) 1 : 2 Explanation: Let the side of the square be x. Then, its diagonal = 2x. Radius of incircle = x/2 and radius of circumcircle =2x2 . Therefore, required ratio = πx24:πx22 = 14:12=1:2
Q: If the labour cost 20% of the cost of production and raw material cost 10% of the cost of production and the price on which article is sold is 20% above the cost of production. If the price of labour is increased by 40% and the price of raw material increased by 20% and rest other expenditure of cost remain constant. The industry thus decide to increase the selling price by 10%. Find the new profit percent ? 1518 05b5cc6c7e4d2b4197774de78
5b5cc6c7e4d2b4197774de78- 118%false
- 220%true
- 322%false
- 424%false
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Answer : 2. "20%"
Explanation :
Answer: B) 20% Explanation: Let the Cost of Production of the article = 100 Then, Labour Cost = 20 Raw Material = 10 Other Expenditure = 100 - 10 – 20 = 70 Selling Price of the article = 120 After increasing Labour and Raw material cost by 40% & 20% respectively, New Labour cost = 28 New Raw material cost = 12 New Cost of Production = 70 + 28 + 12 = 110 Then, New SP = 110% of 120 = 120 x 110/100 = 132 => New Gain = 132 - 110 = 22 => New Profit % = 22 x 100/110 = 20%
Q: In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ? 1517 05b5cc774e4d2b41977750011
5b5cc774e4d2b41977750011- 1205false
- 2194false
- 3209true
- 4159false
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Answer : 3. "209"
Explanation :
Answer: C) 209 Explanation: We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (C16× C34) + C26×C24 + (C36× C14) + (C46) = (24+90+80+15) = 209.
Q: A class has 8 football players. A 5-member team and a captain will be selected out of these 8 players. How many different selections can be made ? 1517 05b5cc6d0e4d2b4197774e38a
5b5cc6d0e4d2b4197774e38a- 1210false
- 2168true
- 31260false
- 410!/6!false
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Answer : 2. "168"
Explanation :
Answer: B) 168 Explanation: we can select the 5 member team out of the 8 in 8C5 ways = 56 ways. The captain can be selected from amongst the remaining 3 players in 3 ways. Therefore, total ways the selection of 5 players and a captain can be made = 56x3 = 168 ways. (or) Alternatively, A team of 6 members has to be selected from the 8 players. This can be done in 8C6 or 28 ways. Now, the captain can be selected from these 6 players in 6 ways. Therefore, total ways the selection can be made is 28x6 = 168 ways.