Quantitative Aptitude Practice Question and Answer
8Q: A laborer is engaged for 30 days on the condition that he receives Rs.25 for each day he works and is fined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many days was he absent ? 1240 05b5cc6dfe4d2b4197774ead0
5b5cc6dfe4d2b4197774ead0- 110 daystrue
- 214 daysfalse
- 311 daysfalse
- 49 daysfalse
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Answer : 1. "10 days"
Explanation :
Answer: A) 10 days Explanation: For 30 days he receives 30 x 25 = 750 Actually he gets 425 Therefore, Fine is 750 - 425 = 325 => No of days absent = 325/(25+7.50)= 10
Q: A sum of money becomes 7/6 of itself in 3 years at a certain rate of simple interest. The rate per annum is ? 1629 05b5cc6dfe4d2b4197774eacb
5b5cc6dfe4d2b4197774eacb- 145/7 %false
- 250/9 %true
- 351/7 %false
- 447/ 9 %false
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Answer : 2. "50/9 %"
Explanation :
Answer: B) 50/9 % Explanation: Let sum = S. Then, amount = 7S/6 S.I. = 7S/6 - S = S/6; Time = 3 years. Rate = (100 x S) / (S x 6 x 3) = 5 5/9 = 50/9 %.
Q: On multiplying a number by 7, the product is a number each of whose digits is 3. The smallest such number is ? 1175 05b5cc6dfe4d2b4197774eac6
5b5cc6dfe4d2b4197774eac6- 1476190476false
- 248617false
- 347619true
- 44587962false
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Answer : 3. "47619"
Explanation :
Answer: C) 47619 Explanation: By hit and trail, we find that 47619 x 7 = 333333. 7) 333333 (47619 333333---------------- 0 And 476190476 x 7 = 3333333333 but smallest number is 47619.
Q: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is ? 1093 05b5cc6dfe4d2b4197774eac1
5b5cc6dfe4d2b4197774eac1- 11 : 2false
- 23 : 1false
- 34 : 7false
- 43 : 2true
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Answer : 4. "3 : 2"
Explanation :
Answer: D) 3 : 2 Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 => 27 x + 17 y = 23 x + 23 y => 4 x = 6 y => x/y = 3/2.
Q: P is faster than Q. P and Q each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then, P's speed is equal to ? 3842 05b5cc6dfe4d2b4197774eab7
5b5cc6dfe4d2b4197774eab7- 13 km/hrfalse
- 24 km/hrtrue
- 35 km/hrfalse
- 46 km/hrfalse
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Answer : 2. "4 km/hr"
Explanation :
Answer: B) 4 km/hr Explanation: Let P's speed = x km/hr. Then, Q's speed = (7 - x) km/ hr. So, 24/x + 24/(7 - x) = 14 x2 - 98x + 168 = 0 (x - 3)(x - 4) = 0 => x = 3 or 4. Since, P is faster than Q, so P's speed = 4 km/hr and Q's speed = 3 km/hr.
Q: A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days ? 1381 05b5cc6dee4d2b4197774ea99
5b5cc6dee4d2b4197774ea99- 19 daysfalse
- 211 daysfalse
- 313 daystrue
- 415 daysfalse
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Answer : 3. "13 days"
Explanation :
Answer: C) 13 days Explanation: Ratio of times taken by A and B = 100 : 130 = 10 : 13.Suppose B takes x days to do the work. Then, 10 : 13 :: 23 : x => x = ( 23 x 13/10 ) => x = 299 /10. A's 1 day's work = 1/23 ;B's 1 day's work = 10/299 . (A + B)'s 1 day's work = ( 1/23 + 10/299 ) = 23/299 = 113 . Therefore, A and B together can complete the work in 13 days.
Q: When 0.46 is written in simplest form, the sum of the numerator and the denominator is ? 1721 05b5cc6dee4d2b4197774ea9e
5b5cc6dee4d2b4197774ea9e- 169false
- 273true
- 396false
- 441false
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Answer : 2. "73"
Explanation :
Answer: B) 73 Explanation: 0.46 = 46/100 = 23/50. Sum of the numerator and denominator is 23 + 50 = 73
Q: The second day of a month is Sunday, What will be the last day of the next month which has 31 days ? 6431 05b5cc6dee4d2b4197774ea94
5b5cc6dee4d2b4197774ea94- 1Fridayfalse
- 2Saturdayfalse
- 3Sundayfalse
- 4Can't be determinedtrue
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Answer : 4. "Can't be determined"
Explanation :
Answer: D) Can't be determined Explanation: We cannot find out the answer because the number of days of the current month is not given.