Quantitative Aptitude Practice Question and Answer

Q: Find the odd man out of the following number series? 22, 26, 42, 78, 142, 244 1628 0

  • 1
    244
    Correct
    Wrong
  • 2
    142
    Correct
    Wrong
  • 3
    78
    Correct
    Wrong
  • 4
    42
    Correct
    Wrong
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Answer : 1. "244"
Explanation :

Answer: A) 244 Explanation: The given number series 22, 26, 42, 78, 142, 244 follows a pattern that, 2222 + 22 = 22 + 4 = 2626 + 42 = 26 + 16 = 4242 + 62 = 42 + 36 = 7878 + 82 = 78 + 64 = 142142 + 102 = 142 + 100 = 242    Hence, the odd one in the given number series is 244.

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Answer : 2. "100"
Explanation :

Answer: B) 100 Explanation: Let the Efficiency of pavan be E(P) Let the Efficiency of sravan be E(S) Here Work W = LCM(25,20) = 100 Now, E(P+2S) = 100/25 = 4 ....(1) E(2P+S) = 100/20 = 5 ....(2) Hence, from (1) & (2) we get E(S) = 1 => Number of days Savan alone work to complete the work  = 100/1 = 100 days.

Q: If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys? 1622 0

  • 1
    4 days
    Correct
    Wrong
  • 2
    6 days
    Correct
    Wrong
  • 3
    7 days
    Correct
    Wrong
  • 4
    5 days
    Correct
    Wrong
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Answer : 1. "4 days"
Explanation :

Answer: A) 4 days Explanation: Given that  6 men and 8 boys can do a piece of work in 10 days  26 men and 48 boys can do the same in 2 days   As the work done is equal, 10(6M + 8B) = 2(26M + 48B) 60M + 80B = 52M + 96B => M = 2B => B = M/2 ……(1)   Now Put (1) in 15M + 20B => 15M + 10M = 25M Now, 6M + 8B in 10 days => (6M + 4M) 10 = 100M Then D(25M) = 100M => D = 4 days.

Q: With an average speed of 40 km/hr, a train reaches its destination in time. If it goes with an average speed of 35 km/hr, it is late by 15 minutes. Find the length of the total journey? 1621 0

  • 1
    70 kms
    Correct
    Wrong
  • 2
    60 kms
    Correct
    Wrong
  • 3
    45 kms
    Correct
    Wrong
  • 4
    30 kms
    Correct
    Wrong
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Answer : 1. "70 kms"
Explanation :

Answer: A) 70 kms Explanation: Let the time taken by train be 't' hrs. Then, 40t = 35t + 1560 40t = 35t + 35/4 t = 7/4 hrs Therefore, Required length of the total journey d = s x t = 40 x 7/4 = 70 kms.

Q: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 1621 0

  • 1
    60%
    Correct
    Wrong
  • 2
    50%
    Correct
    Wrong
  • 3
    70%
    Correct
    Wrong
  • 4
    45%
    Correct
    Wrong
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Answer : 3. "70%"
Explanation :

Answer: C) 70% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420. New C.P. = 125% of Rs. 100 = Rs. 125New S.P. = Rs. 420. Profit = Rs. (420 - 125) = Rs. 295 Required percentage = (295/420) * 100 = 70%(approx)

Q: Two numbers are respectively 40% and 30% more than a third number. The second number expressed in terms of percentage of the first is ? 1620 0

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    92.8%
    Correct
    Wrong
  • 2
    84.23%
    Correct
    Wrong
  • 3
    87.14%
    Correct
    Wrong
  • 4
    94.1%
    Correct
    Wrong
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Answer : 1. "92.8%"
Explanation :

Answer: A) 92.8% Explanation: Here, x = 40 and y = 30;Therefore second number= [[100+y100+x] x 100 ]% of first number= [[100+y100+x] x 100 ]% of first numberSecond number = 92.8% of the first number.

Q: A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red. 1620 0

  • 1
    23/42
    Correct
    Wrong
  • 2
    19/42
    Correct
    Wrong
  • 3
    7/32
    Correct
    Wrong
  • 4
    16/39
    Correct
    Wrong
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Answer : 2. "19/42"
Explanation :

Answer: B) 19/42 Explanation: A red ball can be drawn in two mutually exclusive ways  (i) Selecting bag I and then drawing a red ball from it.   (ii) Selecting bag II and then drawing a red ball from it.   Let E1, E2 and A denote the events defined as follows: E1 = selecting bag I, E2 = selecting bag II A = drawing a red ball Since one of the two bags is selected randomly, therefore  P(E1) = 1/2  and  P(E2) = 1/2 Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7   PAE2  = Probability of drawing a red ball when the second bag has been selected = 2/6  Using the law of total probability, we have   P(red ball) = P(A) = PE1×PAE1+PE2×PAE2                              = 12×47+12×26=1942

Q: A Committee of 5 persons is to be formed from a group of 6 gentlemen and 4 ladies. In how many ways can this be done if the committee is to be included atleast one lady? 1620 0

  • 1
    123
    Correct
    Wrong
  • 2
    113
    Correct
    Wrong
  • 3
    246
    Correct
    Wrong
  • 4
    945
    Correct
    Wrong
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Answer : 3. "246"
Explanation :

Answer: C) 246 Explanation: A Committee of 5 persons is to be formed from 6 gentlemen and 4 ladies by taking.    (i) 1 lady out of 4 and 4 gentlemen out of 6  (ii) 2 ladies out of 4 and 3 gentlemen out of 6  (iii) 3 ladies out of 4 and 2 gentlemen out of 6  (iv) 4 ladies out of 4 and 1 gentlemen out of 6    In case I the number of ways = C14×C46 = 4 x 15 = 60  In case II the number of ways = C24×C36 = 6 x 20 = 120  In case III the number of ways = C34×C26 = 4 x 15 = 60 In case IV the number of ways = C44×C16 = 1 x 6 = 6    Hence, the required number of ways = 60 + 120 + 60 + 6 = 246

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