Quantitative Aptitude Practice Question and Answer
8Q: Find the odd man out of the following number series? 22, 26, 42, 78, 142, 244 1628 05b5cc619e4d2b4197774b70a
5b5cc619e4d2b4197774b70a- 1244true
- 2142false
- 378false
- 442false
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Answer : 1. "244"
Explanation :
Answer: A) 244 Explanation: The given number series 22, 26, 42, 78, 142, 244 follows a pattern that, 2222 + 22 = 22 + 4 = 2626 + 42 = 26 + 16 = 4242 + 62 = 42 + 36 = 7878 + 82 = 78 + 64 = 142142 + 102 = 142 + 100 = 242 Hence, the odd one in the given number series is 244.
Q: Pavan and Sravan are two persons. If Pavan works with his actual efficiency and Sravan twice of his actual efficiency then it takes 25 days to complete the work. But If Pavan works twice of his actual efficiency and Sravan with his normal efficiency then the work is completed in 20 days. How many days would it take if Sravan alone works with his actual efficiency (in Days)? 1628 05b5cc6c7e4d2b4197774ded2
5b5cc6c7e4d2b4197774ded2- 150false
- 2100true
- 370false
- 435false
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Answer : 2. "100"
Explanation :
Answer: B) 100 Explanation: Let the Efficiency of pavan be E(P) Let the Efficiency of sravan be E(S) Here Work W = LCM(25,20) = 100 Now, E(P+2S) = 100/25 = 4 ....(1) E(2P+S) = 100/20 = 5 ....(2) Hence, from (1) & (2) we get E(S) = 1 => Number of days Savan alone work to complete the work = 100/1 = 100 days.
Q: If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys? 1622 05b5cc6b9e4d2b4197774d72a
5b5cc6b9e4d2b4197774d72a- 14 daystrue
- 26 daysfalse
- 37 daysfalse
- 45 daysfalse
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Answer : 1. "4 days"
Explanation :
Answer: A) 4 days Explanation: Given that 6 men and 8 boys can do a piece of work in 10 days 26 men and 48 boys can do the same in 2 days As the work done is equal, 10(6M + 8B) = 2(26M + 48B) 60M + 80B = 52M + 96B => M = 2B => B = M/2 ……(1) Now Put (1) in 15M + 20B => 15M + 10M = 25M Now, 6M + 8B in 10 days => (6M + 4M) 10 = 100M Then D(25M) = 100M => D = 4 days.
Q: With an average speed of 40 km/hr, a train reaches its destination in time. If it goes with an average speed of 35 km/hr, it is late by 15 minutes. Find the length of the total journey? 1621 05b5cc662e4d2b4197774be9c
5b5cc662e4d2b4197774be9c- 170 kmstrue
- 260 kmsfalse
- 345 kmsfalse
- 430 kmsfalse
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Answer : 1. "70 kms"
Explanation :
Answer: A) 70 kms Explanation: Let the time taken by train be 't' hrs. Then, 40t = 35t + 1560 40t = 35t + 35/4 t = 7/4 hrs Therefore, Required length of the total journey d = s x t = 40 x 7/4 = 70 kms.
Q: In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 1621 05b5cc723e4d2b4197774f67c
5b5cc723e4d2b4197774f67c- 160%false
- 250%false
- 370%true
- 445%false
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Answer : 3. "70%"
Explanation :
Answer: C) 70% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420. New C.P. = 125% of Rs. 100 = Rs. 125New S.P. = Rs. 420. Profit = Rs. (420 - 125) = Rs. 295 Required percentage = (295/420) * 100 = 70%(approx)
Q: Two numbers are respectively 40% and 30% more than a third number. The second number expressed in terms of percentage of the first is ? 1620 05b5cc75ce4d2b4197774fc43
5b5cc75ce4d2b4197774fc43- 192.8%true
- 284.23%false
- 387.14%false
- 494.1%false
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Answer : 1. "92.8%"
Explanation :
Answer: A) 92.8% Explanation: Here, x = 40 and y = 30;Therefore second number= [[100+y100+x] x 100 ]% of first number= [[100+y100+x] x 100 ]% of first numberSecond number = 92.8% of the first number.
Q: A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the ball drawn is red. 1620 05b5cc7d0e4d2b4197775121d
5b5cc7d0e4d2b4197775121d- 123/42false
- 219/42true
- 37/32false
- 416/39false
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Answer : 2. "19/42"
Explanation :
Answer: B) 19/42 Explanation: A red ball can be drawn in two mutually exclusive ways (i) Selecting bag I and then drawing a red ball from it. (ii) Selecting bag II and then drawing a red ball from it. Let E1, E2 and A denote the events defined as follows: E1 = selecting bag I, E2 = selecting bag II A = drawing a red ball Since one of the two bags is selected randomly, therefore P(E1) = 1/2 and P(E2) = 1/2 Now, PAE1 = Probability of drawing a red ball when the first bag has been selected = 4/7 PAE2 = Probability of drawing a red ball when the second bag has been selected = 2/6 Using the law of total probability, we have P(red ball) = P(A) = PE1×PAE1+PE2×PAE2 = 12×47+12×26=1942
Q: A Committee of 5 persons is to be formed from a group of 6 gentlemen and 4 ladies. In how many ways can this be done if the committee is to be included atleast one lady? 1620 05b5cc7d1e4d2b41977751286
5b5cc7d1e4d2b41977751286- 1123false
- 2113false
- 3246true
- 4945false
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Answer : 3. "246"
Explanation :
Answer: C) 246 Explanation: A Committee of 5 persons is to be formed from 6 gentlemen and 4 ladies by taking. (i) 1 lady out of 4 and 4 gentlemen out of 6 (ii) 2 ladies out of 4 and 3 gentlemen out of 6 (iii) 3 ladies out of 4 and 2 gentlemen out of 6 (iv) 4 ladies out of 4 and 1 gentlemen out of 6 In case I the number of ways = C14×C46 = 4 x 15 = 60 In case II the number of ways = C24×C36 = 6 x 20 = 120 In case III the number of ways = C34×C26 = 4 x 15 = 60 In case IV the number of ways = C44×C16 = 1 x 6 = 6 Hence, the required number of ways = 60 + 120 + 60 + 6 = 246